is this a coupling or bypass cap??

hi again everyone, another noob question. is this a coupling or bypass capacitor ? and would changing the value improve the sound ?
this is a rotel model RB-850

regards
gaz
 

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This capacitor is in the negative feedback network.
At high frequencies, the amplifier gain is the ratio of the two resistors, R637/R611 + 1.
At low frequencies, the gain reduces due to the capacitor, until it approaches 0dB (x1) at DC.
This is a common approach in power amplifiers to avoid large output DC voltage offset.
It would be best to leave the capacitance value as it is.
 
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It's a capacitor that is part of the feedback network. It reduces the DC gain to unity to limit the DC offset at the amplifier output. It also gives some low-frequency roll-off below a frequency of 1/(2 pi R611 (C605 + C607)) ~= 3.3862 Hz (assuming C607's value is in uF, which I'm sure it is). You can shift that corner frequency by changing C607 if you like. If C607 is a tantalum capacitor, changing it into an aluminium electrolytic capacitor (preferably a bipolar one) may slightly reduce distortion.

Edit: I see rayma was quicker in replying.
 
R637, R611 and C605+C607 are indeed a voltage divider. The gain of the amplifier is ideally (if the open-loop gain were infinite) equal to the attenuation of the feedback divider. So when the feedback voltage divider attenuates 22.3 times, the amplifier amplifies almost 22.3 times (almost, because the open-loop gain is never really infinite).
 
It's the reciprocal of R611/(R637 + R611) rounded to three digits. I don't like rounding numbers, but it was just an example anyway.

By the way, there is also a voltage divider R601, C601, R603, C603 at the input that reduces the gain a bit, I didn't take that into account.
 
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