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iPod/BlackBerry/MP3 input

rsumperl

Member
Paid Member
2009-10-16 9:31 pm
Cascade, Idaho
Hello everyone,
If designing an input for an iPod/BlackBerry/MP3 player, should I use an "R" or a "C" and what value would you think? Everything that I have found online states these players use 32 ohm headsets, thus the 33 ohm resistor, and that the max power out is 30mW. Doing the math, that's around a volt.

Thanks,
Ray
 

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M Gregg

Disabled Account
2010-06-28 11:04 pm
UK
Hello everyone,
If designing an input for an iPod/BlackBerry/MP3 player, should I use an "R" or a "C" and what value would you think? Everything that I have found online states these players use 32 ohm headsets, thus the 33 ohm resistor, and that the max power out is 30mW. Doing the math, that's around a volt.

Thanks,
Ray

For interest you do not need the 33 ohm resistor to "load" the Ipod. What ever has been used at the input is fine. However the output from the H/P socket is not as good as the Ipod connector output. So a charge lead with audio out is better. It does not have a volume control so the input from the Ipod needs to go into a volume control. Many will argue that direct in with no cap is best, however I do like to have cap isolation to something you may hold in your hand. 1uF paper or polyprop works well!:)

Take a look here:
http://www.diyaudio.com/forums/solid-state/172479-ipod-nano-dock.html


Regards
M. Gregg
 
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M Gregg

Disabled Account
2010-06-28 11:04 pm
UK
My thought was to have a 3.5mm jack so that I could use a 3.5mm to 3.5mm cable. I thought that would be more "universal" whether I use an iPod/MP3 player or a BlackBerry.

I have done what you describe, you just need to connect it as any other input only using the 3.5 socket. It works OK. However I wanted to charge the Ipod as well when in use. Forget the H/P load and connect as normal with a 1uF input cap for safety!
You could just use a lead with 3.5mm plug to 2 phono plugs and connect them to any input!<<< I now know this is better because there is no chance of shorting the Ipod H/P out when you connect to the socket, however this is short protected!:)

Regards

M. Gregg
 
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I assume the "units" would like to see a load for proper audio response. That's why I thought of the 33 ohm resistor.

Your looking for maximum voltage transfer rather than maximum power transfer. Putting in a 33 ohm resistor will lose a considerable amount of voltage.

A normal system with a mixer and amplifier has a mixer output impedance of a few ohms while the amplifier will typically have an input impedance of 47K.