Confirmed, the volume is applied in the digital mixer. Having the volume at -30db leaves you with a stunning 11bits... With 8 bit the quantisation gets easily audible.
Having a 24bit DA output is of course something else.
Mike
Having a 24bit DA output is of course something else.
Mike
Mike,
You actually took the time to figure that out! I was about to reply that you are left with reduced bit depth and leave it at that.
The best solution would be a box with a pair of buffers before and after the volume control. In other words, a preamp with possibly two inputs (so you could compare and external DAC as well).
-Chris
You actually took the time to figure that out! I was about to reply that you are left with reduced bit depth and leave it at that.
The best solution would be a box with a pair of buffers before and after the volume control. In other words, a preamp with possibly two inputs (so you could compare and external DAC as well).
-Chris
AndrewT said:
I believe MLP is applied to audio, not video. It's the encoding form used for DVD-Audio (as contrasted to DVD-Video with audio tracks) when running full bandwidth 6-channels (i.e. 192K/24b).
MLP is not needed when running stereo, even at 192/24, since the DVD's standard data rate is enough to handle that (but some disks still encode it with MLP anyway).
Cheers!
Is it best to leave the volume control at full volume on the computer? This ensures it doesn't reduce any bit depth. I will use an external volume control. Probably just passive because it is a lot easier to build or should I spend the time building a pre-amp.
Hi suspencefull,
Do yourself a favour and do it properly. You will need an active buffer in order to preserve the full 16 bits of resolution. A standard "passive" can not deliver that. Then just treat your sound card or DAC as a line level device.
-Chris
Do yourself a favour and do it properly. You will need an active buffer in order to preserve the full 16 bits of resolution. A standard "passive" can not deliver that. Then just treat your sound card or DAC as a line level device.
-Chris
Hi Anatech,
Noise due to reduced signal level I understand.
Poor matching of source impedance to pot impedance and pot source impedance to receiver input impedance, again I understand.
But why your comment?
Please explain.
why won't an analogue pot achieve the same 16bit resolution?
Noise due to reduced signal level I understand.
Poor matching of source impedance to pot impedance and pot source impedance to receiver input impedance, again I understand.
But why your comment?
Please explain.
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