Hey guys i'm trying to figure out how to read an impedance chart that has no ohm markings. For example this one.
I've attached an image of the plot of an audax Audax HP100M0.
I need to trace the impedance plot into passive crossover designer but i can't mark low ohm high ohm with out knowing what each bar represents in ohms. The nominal impedance is 6 ohms.
Thank you and any input is appreciated.
I've attached an image of the plot of an audax Audax HP100M0.
I need to trace the impedance plot into passive crossover designer but i can't mark low ohm high ohm with out knowing what each bar represents in ohms. The nominal impedance is 6 ohms.
Thank you and any input is appreciated.
Attachments
I can't be specific but manufacturers impedance plots I have used typically are logarithmic. Typically doubling each division (2,4,8,16). The resonance peak looks a little rounded rather than pointed and this suggests this plot might be logarithmic too.
BTW, your box will change the bottom end of this plot.
Also, there is no impedance phase data which will be necessary for building a passive crossover.
BTW, your box will change the bottom end of this plot.
Also, there is no impedance phase data which will be necessary for building a passive crossover.
Looking at some other Audax graphs implies they scale the impedance trace so that zeo ohms coincides with one of the amplitude lines that end in zero, then each line above that is 5 ohms apart.
An externally hosted image should be here but it was not working when we last tested it.
Thank You everyone for your useful replies. Here is a link to the original PDF file. http://www.madisound.com/pdf/audax/hp100m0.pdf
So if i gather correctly the flattest part of the curve is Re?
And the ohm markers are at 2 per each division ?
Or is it logarithmic. See its rather important that i can trace the curve accurately in Passive Crossover Designer.
Again thank you.
So if i gather correctly the flattest part of the curve is Re?
And the ohm markers are at 2 per each division ?
Or is it logarithmic. See its rather important that i can trace the curve accurately in Passive Crossover Designer.
Again thank you.
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