Thank You ( s )
I had it right , but wanted to check .
Sometimes db ' s confuse me : (
FWIW here is the amp in question :
https://www.nxp.com/docs/en/data-sheet/TDA7052.pdf
I had it right , but wanted to check .
Sometimes db ' s confuse me : (
FWIW here is the amp in question :
https://www.nxp.com/docs/en/data-sheet/TDA7052.pdf
In electronics dB (as opposed to dBV, dBu, dBm) is a always refering to a notional power ratio, even when not talking about power, which means for current and voltage you square the ratio first, and sometimes you need to be careful to explain if you are talking power, voltage or current.
In RF systems with 50 ohm impedance everywhere then power/voltage/current gains are identical expressed in dB.
In RF systems with 50 ohm impedance everywhere then power/voltage/current gains are identical expressed in dB.
Just to be absolutely clear, its 20 * log10 (Vo/Vi)
making it explicit its the base-10 logarithm. The factor of two comes from the squaring of voltage, you can also do the equivalent:
10 * log10 ((Vo/Vi)^2)
voltage-squared (and current-squared) scales as power (since impedance is held constant).
making it explicit its the base-10 logarithm. The factor of two comes from the squaring of voltage, you can also do the equivalent:
10 * log10 ((Vo/Vi)^2)
voltage-squared (and current-squared) scales as power (since impedance is held constant).
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