Yes but how? Do I convert the dB numbers back to voltage ratio, RMS sum the voltage ratios and then convert to dB? Seems a bit awkward, must be a simpler way.
Jan
Hi Jan,
It would seem to me that you can't add these numbers directly. The resulting number we get from the meter is like a DC value on a meter, but it is derived from a chaotic waveform composed of noise from every connection that exists while you are measuring. I think you would have to add the squares and take the root in order to get a good guesstimate.
Nothing in electronics is that easy as a scalar addition of two entirely different wave forms unless the delta T approaches 0.
-Chris
It would seem to me that you can't add these numbers directly. The resulting number we get from the meter is like a DC value on a meter, but it is derived from a chaotic waveform composed of noise from every connection that exists while you are measuring. I think you would have to add the squares and take the root in order to get a good guesstimate.
Nothing in electronics is that easy as a scalar addition of two entirely different wave forms unless the delta T approaches 0.
-Chris
Chris, point taken. I think for worst-case I should assume that there is no (partial) cancellation. But surely many of the heavy lifters here have been confronted with the issue and I would really hate to re-invent the wheel, again!
Jan
The numbers are spectral components, no noise.
I should check the analyzer manual to see how they calculate with this stuff to get THD from the separate components.
Jan
Couldn't you just convert into percentages and add those for a total?
Doing just that with your given numbers (-110dB + -105dB) gives me a total of 0.0008785% or -101.1251dB.
No idea if that is anywhere near reality though. Someone else would have to disprove or confirm.
Not sure if the limited number of decimal points of the online calculator I used is sufficiently accurate though.
Doing just that with your given numbers (-110dB + -105dB) gives me a total of 0.0008785% or -101.1251dB.
No idea if that is anywhere near reality though. Someone else would have to disprove or confirm.
Not sure if the limited number of decimal points of the online calculator I used is sufficiently accurate though.
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Hmmm. Interesting approach, although it would be a bit different for my numbers because -105 is the result of a generator at -110 and ´X´ resulting in finally -105. So in your approach X would be -110 - -105. I think.
Jan
That can't be right though, can it?
Surely the total distortion of the chain must be slightly higher than that of the device with the highest distortion in the chain.
Otherwise THD would subtract by running a signal through multiple devices.
Yeah I guess so. Hmmm. So it would be something like a complex addition or subtraction. probably for each separate harmonic.
Jan
Sorry, missed that bit. I assumed wrongly that you were running a signal through two devices with known THD levels and wanted to predict the result.
Hi Jan,
I was more trying to have you see how much noise compared to signal there would be. This might determine how you add the numbers up. Yes, phase is not considered by looking at the result on the spec-an, but the real time addition or subtraction might show as you looked at each harmonic. A selective voltmeter might be handy right about now. (eg: HP 3581 type). A steady reading would tell you the sources are correlated.
-Chris
I was more trying to have you see how much noise compared to signal there would be. This might determine how you add the numbers up. Yes, phase is not considered by looking at the result on the spec-an, but the real time addition or subtraction might show as you looked at each harmonic. A selective voltmeter might be handy right about now. (eg: HP 3581 type). A steady reading would tell you the sources are correlated.
-Chris
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