I agree,
You are so caught up on transistors that you are forgetting the basics. Fine, you have +/- 70 volts. How much current does the transformer give? POWER is P=I*E, where I is voltage. If your transformer gives 70V @ 10A (on one rail) 70*10= 700W for that rail. Will it be able to produce 700W? NO! 700 is assuming 100% efficiency, which nothing has. By the time you get 10A out of that rail, the voltage will be far less than 70, possibly 58V, depending on your transformer, so your PK/PK voltage suffers and your output voltage goes down. Adding transistors only improves the current carrying capability and low impedance driving capabilities. This means the more transistors, the less impedance your amp poses so the load gets the power instead of your heatsink. More transistors doesn't give an amp more power, the power supply does... Transistors and worrying about how to increase the gain of the amp is the last thing to worry about. If you already have 5 or more output transistors, forget it, nothing else will help aside a second power transformer in parallel, which is a feat in itself due to voltage differences. Be careful about changing outputs and drivers.... You want to keep the gain, and Ft to be very close while upgrading to higher voltage and current rating...... Good luck,
Chris
You are so caught up on transistors that you are forgetting the basics. Fine, you have +/- 70 volts. How much current does the transformer give? POWER is P=I*E, where I is voltage. If your transformer gives 70V @ 10A (on one rail) 70*10= 700W for that rail. Will it be able to produce 700W? NO! 700 is assuming 100% efficiency, which nothing has. By the time you get 10A out of that rail, the voltage will be far less than 70, possibly 58V, depending on your transformer, so your PK/PK voltage suffers and your output voltage goes down. Adding transistors only improves the current carrying capability and low impedance driving capabilities. This means the more transistors, the less impedance your amp poses so the load gets the power instead of your heatsink. More transistors doesn't give an amp more power, the power supply does... Transistors and worrying about how to increase the gain of the amp is the last thing to worry about. If you already have 5 or more output transistors, forget it, nothing else will help aside a second power transformer in parallel, which is a feat in itself due to voltage differences. Be careful about changing outputs and drivers.... You want to keep the gain, and Ft to be very close while upgrading to higher voltage and current rating...... Good luck,
Chris
...where I is the voltage?!? Ususally this means the current. Talk about forgetting the basics... 🙄Diode said:I agree,
You are so caught up on transistors that you are forgetting the basics. Fine, you have +/- 70 volts. How much current does the transformer give? POWER is P=I*E, where I is voltage.
/Marcus
Blow fuses?
I've been following this thread for a while. I also find that my whiskey bottle is dwindling rather rapidly. They are now asking me why I am talking so loud to myself !
Now someone is knocking at my door. Good God, they are carrying a strait jacket.... Help !! Its not me .... it is that guy with THE amp !!!!! Helllllp ...................
Sorry. I couln't help it...........no offense meant.
Cheers.
Since I have encountered DJ's questions before I have been following this thread to see when someone's fuse would blow
I've been following this thread for a while. I also find that my whiskey bottle is dwindling rather rapidly. They are now asking me why I am talking so loud to myself !
Now someone is knocking at my door. Good God, they are carrying a strait jacket.... Help !! Its not me .... it is that guy with THE amp !!!!! Helllllp ...................
Sorry. I couln't help it...........no offense meant.
Cheers.
I've been searching for a while to find speakers that match
the quality of the pictures DJ has provided. Kind of tough
to do.
The top one here is probably better than what he is using.
http://www.speakermax.com/catalog/405.fr215/405.fr215.html
please note this spec
240 watts continuous, 500 watts peak. 4 ohms
(and this is way overrated i think)
I will repeat that 1800 watts and 2 ohms is pure Cow droppings.
the quality of the pictures DJ has provided. Kind of tough
to do.
The top one here is probably better than what he is using.
http://www.speakermax.com/catalog/405.fr215/405.fr215.html
please note this spec
240 watts continuous, 500 watts peak. 4 ohms
(and this is way overrated i think)
I will repeat that 1800 watts and 2 ohms is pure Cow droppings.
Kevin, what about this?
http://www.mackie.com/sr/sa1232/
Sorry, acitve speaker, 3000 W amp! Something for DJ, everything is ready
http://www.mackie.com/sr/sa1232/
Sorry, acitve speaker, 3000 W amp! Something for DJ, everything is ready

I think mackie is a bit beyond DJ's pricing demands.
2000 watt speakers <= 100$ each
3000 watt amplifier <= 159$ each
2000 watt speakers <= 100$ each
3000 watt amplifier <= 159$ each
e96mlo said:
...where I is the voltage?!? Ususally this means the current. Talk about forgetting the basics... 🙄
/Marcus
Maybe you have forgotten the basics? He said "P = I*E". It is
common to denote the voltage of a DC source with the letter
E. Especially, this is very common in swedish textbooks, so it
is very surprising you should be surprised. If asked whether
it is used in the english literature, I would not have dared
a guess, but it seems from this poster that it is used also
there. 🙂
kevin gilmore said:I think mackie is a bit beyond DJ's pricing demands.
2000 watt speakers <= 100$ each
3000 watt amplifier <= 159$ each
Hi all,
in first ca 20 posts DJ make joke with all us, in next posts you guys make same thing with DJ. Isnt this offtopic? I have notification on this thread ON, but obviusly this is wrong.
🙁
zzeenn
Yup.
I think we better end this thread.
Nothing much wrong with DJ's approach , it's just different. It is just that sometimes we tend to pounce on such posts - mostly for some fun I guess. I am sure all of it was very light hearted.
DJ can start another one after he does some more tweaking.
Cheers.
I think we better end this thread.
Nothing much wrong with DJ's approach , it's just different. It is just that sometimes we tend to pounce on such posts - mostly for some fun I guess. I am sure all of it was very light hearted.
DJ can start another one after he does some more tweaking.
Cheers.
I couldn't agree more about the voltage source and the letter for it but I was talking about the letter I. This usually means current in most textbooks, wether they are from Sweden or not.Christer said:Maybe you have forgotten the basics? He said "P = I*E". It is
common to denote the voltage of a DC source with the letter
E. Especially, this is very common in swedish textbooks, so it
is very surprising you should be surprised. If asked whether
it is used in the english literature, I would not have dared
a guess, but it seems from this poster that it is used also
there. 🙂
If P=I*E and E=voltage, then I=current.
/Marcus
e96mlo said:
I couldn't agree more about the voltage source and the letter for it but I was talking about the letter I. This usually means current in most textbooks, wether they are from Sweden or not.
If P=I*E and E=voltage, then I=current.
/Marcus
Sorry, I must have read the original post sloppily. I missed
that he explicitly said "I is the voltage".
Edit: I guess my brain uses to ignore certain obvious typos.
Here the formula was correct, so I probably didn't even think
about if the text was consistent with it. Since the posting was
intended as educational, i fully agree that such consistency
is important.
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