Help about transformer for PWM Power Supply

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Dbnn

Hello there,
I'm start building an audio amplifier about 2x120w RMS @ 8ohms and 4 or 8ohms stable Class AB.
Output devices are 2*2SA1943 / 2*2SC5200 each channel.
I want running this about +/-60vDC, so for 4ohms usage is need too many amperage.
To use standard transformer is too expensive and too heavy.
The amp is intended for mobile DJ usage so i want to keep it light and DONT heavy.

I have circuit for classic half bridge TL494 for drive and lots of high voltage / amperage FETs from old computer PSUs.
But i'm confused about transformer. i have lots of ferrite cores and classic "EI" from computer PSUs to change the primary / secondary windings. Also i have insulated wire about 0.6, 0.8, 1, 1.2mm thickness.
So what is the calculation for one primary winding or two primary windings to get the result for 2 secondary windings to take 2x60vDC rectified?
For car audio transformers i use the calculator from here:
Basic Switching Power Supply Design Tutorial
and i'm changing the running voltage for my car amps with totally success.
But the main voltage now is >300vDC and i'm affraid to make experiments

I like the opinion from this community because something you know more than me.
Regards.

nigelwright7557

The ratio of primary turns to secondary turns is 4.
That is 4 on primary to 1 on secondary.

I would guess about 20 turns on primary to 5 on secondary to get 60volts.

V=n×A×B×4×f
SI.

Dbnn

V=n×A×B×4×f
SI.

can you explain that parameters please? i mean, n,A,B,4,f
i think is V voltage, A ampere, f frequency.

n = turns
A = Amperes?
B = flux Tesla?
f = frequency Hz

Dbnn

n = turns
A = Amperes?
B = flux Tesla?
f = frequency Hz

B= wire thickness ??
A= Amperes but i'm not 100% sure.

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