The simplest solution is 3 10 watt resistors to spread out the heat.
Well, I had planned a single 19R in the CRC, but I think you have a point there. spreading out the heat would be a good idea.
No love for the resistors in series with the diodes?
Cassiel, would you like a sip of this really nice craft bourbon?
Yes, I would but I'm too wasted already. 🙂
I would buy a choke if there's space in the chassis but first, read this because I don't know what kind of rectifier are you using.
http://www.hammondmfg.com/pdf/5c007.pdf
No love for the resistors in series with the diodes?
Each diode would only drop 0v7 so you would need quite a few.
Using a couple of 6 volt 5 watt zeners in series is another possibility.
I don't have a schematic for this power supply, but you can see that resistors are used in series with the 1N4007 diodes. To what purpose?
Let me guess your transformer is a 12-0-12 and you're using a bridge rectifier. Then, no luck. Choke input won't give you enough volts. Another post with wrong info from me then and that makes four, where do I get the medal? 🙂
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I don't have a schematic for this power supply, but you can see that resistors are used in series with the 1N4007 diodes. To what purpose?
Forget about those. That is a high voltage low current supply. Yours is pulling 600mA!!!! Think in Ohms law.
The rectified DC from the replacement PT (after diodes, before CRC) puts up about 36vdc rather than 28vdc as spec'd on the drawing.
Is the 36vdc with or without any valves plugged in?
If it is with valves, then yes, you need to loose some volts.
If it is without, then you don't yet know how many volts you need to drop, since the voltage will fall when current is drawn, and possibly to the level where no additional voltage dropping is needed.
Is the 36vdc with or without any valves plugged in?
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Looks like those 36vdc don't even see a cap input. All this trouble for nothing. Oh well, it was fun.
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