I'm pretty sure they've been posted in the past, but I can't seem to find them. I was just wondering what the formulas were to figure out the length and width of a screen 4:3 or 16:9 if you have the size x" . Thanks
You just have to try to remember back to your high school math days for a bit of trig (Pythagorean theorem, sin, cos, tan, etc) to get the values. Anyway, here you go:
4:3 screen with diagonal x: h = 0.60*x, w = 0.80*x
16:9 screen with diagonal x: h= 0.49*x, w = 0.87*x
Keep in mind, these are approximations for the 16:9, as the values (0.49 and 0.87) are rounded off. The exact values would be expressed as square roots or sines/cosines. Hope this helps.
4:3 screen with diagonal x: h = 0.60*x, w = 0.80*x
16:9 screen with diagonal x: h= 0.49*x, w = 0.87*x
Keep in mind, these are approximations for the 16:9, as the values (0.49 and 0.87) are rounded off. The exact values would be expressed as square roots or sines/cosines. Hope this helps.
LaserLine said:
This formula was originally posted by Romp in DIY Video Projector Part II Page 69 - I'm by no means sure of it's accuracy...
Lu = ( 1 - cos(beam_width/2)) * 2pi * cd
As you can see it also depends on the divergence of the bulb/LED
Hope this helps,
Steve
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