I have alot of 6 of these diods. There should be 4 E202 and 2 E562,how do I mesure them so I se wich is wich?
Are they not labelled ?
Looks like they should have apart number on them.
E562
Current Regulator Diodes 100V 5.6mA
https://www.mouser.com/ProductDetail/Semitec/E-562?qs=wgO0AD0o1vudQ6PtNBE4BA==
E202
Current Regulator Diodes 100V 2mA
https://www.mouser.com/ProductDetail/Semitec/E-202?qs=wgO0AD0o1vtsf3eUHD2UhA==
Looks like they should have apart number on them.
E562
Current Regulator Diodes 100V 5.6mA
https://www.mouser.com/ProductDetail/Semitec/E-562?qs=wgO0AD0o1vudQ6PtNBE4BA==
E202
Current Regulator Diodes 100V 2mA
https://www.mouser.com/ProductDetail/Semitec/E-202?qs=wgO0AD0o1vtsf3eUHD2UhA==
Thanks for the answers,I used my bench supply at 12v and a resistor but somehow the 600mA fuse in my DMM blew...
Now I ended up ordering new diodes from ebay hoping the bags are labeled properly.
Now I ended up ordering new diodes from ebay hoping the bags are labeled properly.
Use a 100 resistor in series, the banded side of the constant current diode goes to the negative with your 12 volt supply.
. The E202 will measure around 0.2 volts ( it varies up to +/-20% ) across the resistor. The voltage across the resistor multiplied by 10 will be the idss of the current source. The E562 will be around 0 .56 volts (+/- 20%)- again multiply by 10 to get the actual idss
. The E202 will measure around 0.2 volts ( it varies up to +/-20% ) across the resistor. The voltage across the resistor multiplied by 10 will be the idss of the current source. The E562 will be around 0 .56 volts (+/- 20%)- again multiply by 10 to get the actual idss
Sommething not right here,
The supply set to 10v shows a current draw of 90mA,I cant have the power on for many seconds before theres smoke from the resistor.
The supply set to 10v shows a current draw of 90mA,I cant have the power on for many seconds before theres smoke from the resistor.
I suspect the marking / connection problem here. Test a new one with DMM like you test a diode, to ensure cathode/anode leads are marked corretly.
Then put into the curcuit like zener - apply a positive voltage to the cathode. Following the assumption the CRD is just a JFET it should work like this.
Then put into the curcuit like zener - apply a positive voltage to the cathode. Following the assumption the CRD is just a JFET it should work like this.
They should be and the datasheet tells the same, but since it behaves like an ordinary diode not so many options left here ))