In other words, if the minimum position (7 O'clock) is 30hz and the maximum position (5 O'clock) is 200hz, one might assume that mid point of 12 O'clock would be around 115hz.
But if a linear pot is used instead of a log pot, the points may be skewed somewhat. Right?
But if a linear pot is used instead of a log pot, the points may be skewed somewhat. Right?
Just got a response from Douk Audio USA customer service:
"
Hello,
80Hz: It is recommended to point the knob towards around 11 o'clock;
100Hz: It is recommended to point in the direction from 12 o'clock to 1 o'clock.
But this is not a fixed value, it is still recommended that you adjust it slowly according to the device."
This is contrary to Amir's measurement for "straight up".
I gather that it's anyone's guess where to set it for 120hz.
I'll try setting it between 1 & 2.
"
Hello,
80Hz: It is recommended to point the knob towards around 11 o'clock;
100Hz: It is recommended to point in the direction from 12 o'clock to 1 o'clock.
But this is not a fixed value, it is still recommended that you adjust it slowly according to the device."
This is contrary to Amir's measurement for "straight up".
I gather that it's anyone's guess where to set it for 120hz.
I'll try setting it between 1 & 2.
Has anyone managed to take any measurements of the high-pass filter knob setting yet?
What do they mean by "not a fixed value". Does it vary from unit to unit? Or do they mean it's logarithmic?
Going by calculations for each of linear and logarithmic pentiometer scenarios. For linear:
If 7 o'clock is 30Hz, 5 o'clock is 200Hz, then each "hour" (7 o'clock to 5 o'clock = 10 hours) equates to 17Hz ((200-30)/10).
Thus:
For logarithmic:
10^(LOG10(30) + f * ((LOG10(200)-LOG10(30))/10))
Thus:
Both appear to be inconsistent with what the customer service are saying.
What do they mean by "not a fixed value". Does it vary from unit to unit? Or do they mean it's logarithmic?
Going by calculations for each of linear and logarithmic pentiometer scenarios. For linear:
If 7 o'clock is 30Hz, 5 o'clock is 200Hz, then each "hour" (7 o'clock to 5 o'clock = 10 hours) equates to 17Hz ((200-30)/10).
Thus:
| Clock position | Frequency (Hz) | Step 👎 |
[td]
7
[/td][td]30
[/td][td]1
[/td][td]
8
[/td][td]47
[/td][td]2
[/td][td]
9
[/td][td]64
[/td][td]3
[/td][td]
10
[/td][td]81
[/td][td]4
[/td][td]
11
[/td][td]98
[/td][td]5
[/td][td]
12
[/td][td]115
[/td][td]6
[/td][td]
1
[/td][td]132
[/td][td]7
[/td][td]
2
[/td][td]149
[/td][td]8
[/td][td]
3
[/td][td]166
[/td][td]9
[/td][td]
4
[/td][td]183
[/td][td]10
[/td][td]
5
[/td][td]200
[/td][td]11
[/td][td]
[td]
[/td][td]
[/td]10^(LOG10(30) + f * ((LOG10(200)-LOG10(30))/10))
[td]
[td]
[/td][td]
[/td]| Clock Pos | Frequency (Hz) | Step 👎 |
| 7 o'clock | ||
| 8 o'clock | ||
| 9 o'clock | ||
| 10 o'clock | ||
| 11 o'clock | ||
| 12 o'clock | ||
| 1 o'clock | ||
| 2 o'clock | ||
| 3 o'clock | ||
| 4 o'clock | ||
| 5 o'clock |
[td]
30.00
[/td][td]0
[/td][td]
36.27
[/td][td]1
[/td][td]
43.84
[/td][td]2
[/td][td]
53.00
[/td][td]3
[/td][td]
64.07
[/td][td]4
[/td][td]
77.46
[/td][td]5
[/td][td]
93.64
[/td][td]6
[/td][td]
113.20
[/td][td]7
[/td][td]
136.85
[/td][td]8
[/td][td]
165.44
[/td][td]9
[/td][td]
200.00
[/td][td]10
[/td]Both appear to be inconsistent with what the customer service are saying.
Reposting due to formatting issues.
Has anyone managed to take any measurements of the high-pass filter knob setting yet?
What do they mean by "not a fixed value". Does it vary from unit to unit? Or do they mean it's logarithmic?
Going by calculations for each of linear and logarithmic pentiometer scenarios.
For linear:
If 7 o'clock is 30Hz, 5 o'clock is 200Hz, then each "hour" (7 o'clock to 5 o'clock = 10 hours) equates to 17Hz ((200-30)/10).
Thus:
For logarithmic:
10^(LOG10(30) + f * ((LOG10(200)-LOG10(30))/10))
Thus:
Both appear to be inconsistent with what the customer service are saying.
Has anyone managed to take any measurements of the high-pass filter knob setting yet?
What do they mean by "not a fixed value". Does it vary from unit to unit? Or do they mean it's logarithmic?
Going by calculations for each of linear and logarithmic pentiometer scenarios.
For linear:
If 7 o'clock is 30Hz, 5 o'clock is 200Hz, then each "hour" (7 o'clock to 5 o'clock = 10 hours) equates to 17Hz ((200-30)/10).
Thus:
Clock position Frequency (Hz) Step (n)7 30 18 47 29 64 310 81 411 98 512 115 61 132 72 149 83 166 94 183 105 200 11For logarithmic:
10^(LOG10(30) + f * ((LOG10(200)-LOG10(30))/10))
Thus:
Clock Pos Frequency (Hz) Step (n)7 o'clock 30.00 08 o'clock 36.27 19 o'clock 43.84 210 o'clock 53.00 311 o'clock 64.07 412 o'clock 77.46 51 o'clock 93.64 62 o'clock 113.20 73 o'clock 136.85 84 o'clock 165.44 95 o'clock 200.00 10Both appear to be inconsistent with what the customer service are saying.