Dont kill me BUT...

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wrong name

I´m sure it sounds nice, but it´s no X!

1) X has no feedback from one amp to the other
2) X uses inverting stages
3) X has just one gainstage and a sourcefollower
4) X is easier to control the offset because of loose coupling

Uli:clown: :clown: :clown:
 
Re: wrong name

uli said:
I´m sure it sounds nice, but it´s no X!

1) X has no feedback from one amp to the other
2) X uses inverting stages
3) X has just one gainstage and a sourcefollower
4) X is easier to control the offset because of loose coupling

Uli:clown: :clown: :clown:

I am no whiz at the X thing obviously but to my knowledge:

1) That is the fundamental of the X topology AFAIK. Without it there is no X.
2) At least one needs to be AFAIK since you want to feed the "error" signal back in opposite phase. The inv. stage has nothing to do with the X as such.
3) Maybe, maybe not. This has nothing to do with the X as such AFAIK.
4) Maybe, maybe not. See 2) and 3).

All of the above replies could naturally be incorrect (although I hope not) but I am sure that some of the X-men (and X-girls) will chip in their 2 cents.
 
The confusion revolves around the op-amp analogy.

What appear to be positive inputs are low impedance
connections, thus they can insert current into each other.

At the - inputs, which are high impedance, you theoretically
only see the error signal, and this appears at the + inputs
by virtue of them being the Source/Emitter where the -
input is the Gate/Base, so they follow, and form a low
impedance load.

In this way, the "+ inputs" communicate current to each
other representing the error signal of each side, causing
the circuit to reproduce the errors of each side in phase.

I know it's confusing.....

pass/ - not seeking confusion except among his
economic competitors.
 
Re: Re: wrong name

UrSv said:

1) That is the fundamental of the X topology AFAIK. Without it there is no X.

I fear that this is not quite correct.
When you look at NPs writing the 2 amps are NOT connected
except the resistor between the +inputs.

2) At least one needs to be AFAIK since you want to feed the "error" signal back in opposite phase. The inv. stage has nothing to do with the X as such.

Of course it has. the errorsignal is fed thru this particular resistor
into the other stage.

3) Maybe, maybe not. This has nothing to do with the X as such AFAIK.

If you stretch X over 2 stages you would have to feed the feedback into the source of the first fet.

4) Maybe, maybe not. See 2) and 3).

All of the above replies could naturally be incorrect (although I hope not) but I am sure that some of the X-men (and X-girls) will chip in their 2 cents.

I´m waiting for NP´s statement, please don´t kill me:dead: :dead: :dead:

Uli
 
Nelson Pass said:


In this way, the "+ inputs" communicate current to each
other representing the error signal of each side, causing
the circuit to reproduce the errors of each side in phase.

I know it's confusing.....

pass/ - not seeking confusion except among his
economic competitors.

A little bit...

This is what I ment when talking +inputs (source).
theres no feedback from one side to the other
exept this (47R) resistor!

When looking at SOZ its a VERY simple kind of X
but NOT those circuits called Aleph X.

I´m sorry confusing anybody.

PS: XSOZ = swapping all those 8R power resistors to CCS´s
putting some feedback from the drains to the particular
gates, adding input resistors swap the 1R to 47R and from the 2
sources to ground a 300R each. Add a DC-path from the inputs
to ground.

I´ll post a drawing ASAP.:bulb:

Uli /-not being any kind of competitor neither economic nor
knowhow wise 🙂 🙂 🙂
 
uli said:

PS: XSOZ = swapping all those 8R power resistors to CCS´s
putting some feedback from the drains to the particular
gates, adding input resistors swap the 1R to 47R and from the 2
sources to ground a 300R each. Add a DC-path from the inputs
to ground.

I´ll post a drawing ASAP.:bulb:

Here you are...
PS: not a working circuit! just an idea
 

Attachments

differential pair = no X

Hi,
looks very similar but is a differential amplifier formed by
Q2 and Q3 with a CCS (Q4) driving 2 quasi-complementary
outputstages.
Its very similar to the "Aleph-X" by Grey (same inputstage)
but instead of Aleph output its a quasicomplementary Emitter
follower outputstage.
Fault is to believe that a symmetrical output from a differential pair (folded cascode or not!) is X-principle!
Otherwise the government would not have granted NP a
patent on this.

Uli
 
argument

You´re right, it would be a weak basement.

But NP himself stated that its possible to X a differential pair
if its a simple (one stage) circuit. ->
I understand that X is different from differential pair!

You just have to read the patent (which is available to the
public as every patent is) carefully!

Spend 3 USD for the complete patent 😉
www.delphion.com

Uli


PS: In AUSTRIA we don´t have cangaroos!
 
uli,

The biggest problem understanding the X circuit generally comes from the schematics shown in the patent. Fact is, the circuit can be made ALOT simpler than it is shown in the patent. If you take a step back and draw functional blocks of each part shown in the patent schematic, you'll see that there is more than one way to skin a cat.
 
difference

ok, in my understanding is the main difference as follows:
The sources of a diff.pair share one CCS
The sources of an X pair have 2 INDEPENDENT but identical
CCS´s loosely coupled by the X-resistor.

With this the errorsignal of one side wich can be seen at the gate
(and nothing else!) is fed from the source into the other source
and therefore both outputs carry the SAME errorsignal IN PHASE
thus the load don´t see any errorsignal anymore

The principle to use both outputs of a diff.pair is as old as active devices!

If I´m wrong, where is the reason for patenting this circuit?:dead: :dead: :dead:
Uli

PS: I love cats, please don´t skin them:devilr: :devilr: :devilr:
 
Re: difference

uli said:
The principle to use both outputs of a diff.pair is as old as active devices!

If I´m wrong, where is the reason for patenting this circuit?:dead: :dead: :dead:
Uli

PS: I love cats, please don´t skin them:devilr: :devilr: :devilr:

It's all in how the feedback is applied. If you look at the attachment in post #1 of 'The Aleph-X' thread, you'll see that the feedback crosses over from one side of the circuit to the other ... this indeed does get the X effect.
 
ok, in my understanding is the main difference as follows:
The sources of a diff.pair share one CCS
The sources of an X pair have 2 INDEPENDENT but identical
CCS´s loosely coupled by the X-resistor.

The use of X-resistor and resistors to ground for the loose coupled CCS´s is only needed in the more complex circiuts (more than two gainstages) preventing the "hall of mirrors effect" by damping the signal in the ongoing feedback repetition. In simple circiuts like Aleph X or XSOZ you simply don´t need them, I think you are better off without them, using just one CCS.
 
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