Hi , for the DEAP thread im searching for a High voltage powersuplly.
i made a cockroft walton cascade but the DEAP is not working , so i looked up what people used as source for the high voltage. im afraid that although it mostly the voltage that is important my output current might be to low ?
they used an EMCO G50 these are the specs
http://www.emcohighvoltage.com/pdfs/gseries.pdf
the output current at 6000 volt is only 0.3mA MAX
my multiplier is fed with 600 VOLT Ac 6mA
then a cockroft multiplier stage of 4 with 47nF capacitors.
im wondereing if i get close to the 0.3mA at the end of it
i made a cockroft walton cascade but the DEAP is not working , so i looked up what people used as source for the high voltage. im afraid that although it mostly the voltage that is important my output current might be to low ?
they used an EMCO G50 these are the specs
http://www.emcohighvoltage.com/pdfs/gseries.pdf
the output current at 6000 volt is only 0.3mA MAX
my multiplier is fed with 600 VOLT Ac 6mA
then a cockroft multiplier stage of 4 with 47nF capacitors.
im wondereing if i get close to the 0.3mA at the end of it
energy conservation applies, can't get more I*V out than in
so similar to transformer - divide current in by step up ratio for max 100% efficiency I out
then guess or compare with others how much fudge factor to account for losses, full/half wave, ect.
charge conservation/capacitor Z at pump frequency gives more droop so sizing the C matters too
so similar to transformer - divide current in by step up ratio for max 100% efficiency I out
then guess or compare with others how much fudge factor to account for losses, full/half wave, ect.
charge conservation/capacitor Z at pump frequency gives more droop so sizing the C matters too
Oh one thing to notice the guy thats uses this Emco stepup never got above 3Kv in his tests and according to the spec sheet you should halve the max current rating when you half the voltage, (kind of the opposite what you just said)
Quate from spec sheet
The rated output current is available at full output voltage and must be derated proportionally as the input
’ voltage decreases. For example: a 500V, 1.5W unit, rated at 3mA at 500V will provide 1.5mA at 250V out.
Quate from spec sheet
The rated output current is available at full output voltage and must be derated proportionally as the input
’ voltage decreases. For example: a 500V, 1.5W unit, rated at 3mA at 500V will provide 1.5mA at 250V out.
Last edited:
- Status
- Not open for further replies.