Calling all clever people :) What do you make of this?

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A quick recap is in place:
Imagine a plane is sat on the beginning of a massive conveyor belt/travelator type arrangement, as wide and as long as a runway, and intends to take off. The conveyer belt is designed to exactly match the speed of the wheels at any given time, moving in the opposite direction of rotation.
What do you think from this??
Only one thing, the plane would never lift off! When you are convinced that this is right, I will convince you of the opposite 😀

Steen😎
 
eVITAERC said:



That is just wrong.

Allright, allright, time for thought experiment

Imagine you're out on a spaceship, in such a mostion that the earth is stationary to you but you can see it rotate. Now imagine you watching a plane cruising on a runway somewhere on earth.

Is it possible that the plane may be going fast enough so that it looks stationary relative to you? Of course, it just has to move at the right speed.

Is it possible to keep the plane stationary to you as it speeds up, no matter how fast it's running relative to the earth? Of course, just "speed up" the earth by the exact same amount.

Now come back to the airport grounds and translate your results. Your "fixed point of refrence" becomes the airport grounds and the earth is now the conveyer belt. The rotational machenics of the wheel and something spinning underneath it is still the same, nothing changed, except maybe you "shrunk" the earth to a conveyer belt. Same thing.

None of the above is relevant. The conveyor belt is simply not in a position to do what you ask of it. It can do no more than turn the wheels. And the wheels are decoupled from the plane by the axle. In a nutshell, the plane and the wheels are free to act independently to the relevant stimulus.
 
rfbrw said:
The bog standard jet engine, not to mention the monstrosities planned for the A380, can pretty much overcome any frictional losses. The bearings would have to seize in order to stop the plane taking off, a feat the belt would have to achieve within seconds of the start of the take off run.
But the plane would have problems if that happened. I think that no matter what, we have to assume that nothing breaks, so there are no limits either to the amount of power the wheels can waste, or how much thrust the engines can produce before they tear off and fly away on their own.


Cal Weldon said:
...So how fast are the wheels turning at takeoff speed?
Depends on which interpretation. The one which is presumably supposed to be the correct one (the conveyor belt moves forward at a speed equal to the plane, relative to the ground) then the wheels never rotate at all. If you instead interpret it as the conveyor belt moving backwards to prevent the wheels moving relative to the ground, then they will have to rotate infinitely fast.
 
My gosh this is fun.

Okay, let's look at the last bit.
The conveyer belt is designed to exactly match the speed of the wheels at any given time, moving in the opposite direction of rotation.
ie, the wheels do not rotate. Have I missed anything? To keep the wheels from moving forward against the force applied by the engine(s) against the air, the belt must move in the direction of the body of the airplane. Dynamically keeping the wheels from moving. The actual movement will be small because every servo must operate with some error. Doesn't matter, airplane has reached rotation and leaves the conveyer. In flight. Bye bye.

-Chris
 
rfbrw said:
None of the above is relevant. The conveyor belt is simply not in a position to do what you ask of it. It can do no more than turn the wheels. And the wheels are decoupled from the plane by the axle. In a nutshell, the plane and the wheels are free to act independently to the relevant stimulus.


I fail to see how there is no analogy between the plane running on a rotating object (the earth) and the plane running on another rotating object (the conveyer). In both cases the mecahnics driving the plane, including all the nitty-gritty "fairy tale physics" about how the wheel is somehow decoupled from the engine in a kinematical sense, is voided because the mechanics of the plane stayed the same. I simply swiched the earth for the conveyer belt, Indiana Jones style.

If the first scenerio (earth) seems plausible to you, there's no reason why the second scenario (conveyer) shouldn't.


Hey look~ The sanding sealer on my new cabs dried 😀 I can get back to working on it now ^^
 
Hi eVITAERC,
I fail to see how there is no analogy between the plane running on a rotating object (the earth) and the plane running on another rotating object (the conveyer).

In the first case the air is moving with the earth and the engines are acting on the air. In the second case the air is not greatly influenced by the conveyer belt so the motion of the plane and the surface are not related.

'Tis the air and the plane you need to worry about.

-Chris
 
Mr Evil said:

I think that no matter what, we have to assume that nothing breaks,

In that case, the plane will always take off


eVITAERC said:



I fail to see how there is no analogy between the plane running on a rotating object (the earth) and the plane running on another rotating object (the conveyer). In both cases the mecahnics driving the plane, including all the nitty-gritty "fairy tale physics" about how the wheel is somehow decoupled from the engine in a kinematical sense, is voided because the mechanics of the plane stayed the same. I simply swiched the earth for the conveyer belt, Indiana Jones style.

If the first scenerio (earth) seems plausible to you, there's no reason why the second scenario (conveyer) shouldn't.


Hey look~ The sanding sealer on my new cabs dried 😀 I can get back to working on it now ^^


Ask yourself this. In the normal course of events, does a plane go forward because the wheels are turning or are the wheels turning because the plane is going forward?
 
anatech said:
Hi sss,
Salt. In Canada we use salt on the ice to stop cars from sliding. Sand might work too. 😉

-Chris



😀 😀 😀
i' triying to help the non believers to understand that the plain will take off
just like those plains on water , no wheels and woooo take off
wheel spin is not important in that situation , they are there to insure free movement of the plain and to brake it while landing , thats all
 
To fly, or not to fly, that is the question.

Hi to all you aircraft enthusiasts.

Pinkmouse is quite correct, as the ground speed (or the surface movement of the ground relative to the plane's position, which is all that is out of the ordinary in this case) has nothing to do with lift, which is what governs the plane's ability to take off (under all other 'normal' circumstances).
Lift is created when the surrounding air flows past the plane's wings, and this lift can be aided to some extent by wind blowing from the front of the plane backwards, or partly countered when the wind blows from the back of the plane forwards.

Indeed, I once saw a Tiger Moth (a quite lightly built canvas covered bi-plane, and ex-WW2 trainer) being tied down to the ground to prevent it from taking off whilst it was completely stationary (relative to the ground) because this plane's stalling speed was only approx. 75 MPH, and the wind was blowing past it from the front at about this speed!
For those who are not aware, the stalling speed of an aircraft is basically the minimum speed it needs to maintain in relation to **the surrounding air**, in order to stop it falling out of the sky.

Also on some of the very early aircraft carriers and with these old lightweight planes, they could actually land moving backwards relative to the ship because the ship's forward motion when added to a strong head-on wind, also exceeded the plane's stalling speed! Nowadays, and with much heavier planes, considerably higher stalling speeds apply.

With any conventional fixed-wing plane, there should be quite sufficient forward thrust to propel the plane through the air **in which it currently resides** (irrespective of the ground's relative position, or movement) and this is the crux of the matter if it is to take off. Also, unless there is something wrong with the landing gear, this will have no bearing on the issue, since as others have tried to point out, the forward thrust is not provided through its wheels, but by the engines (propellor or jet) forcing air backwards. The wheels will rotate quite happily, if necessary, either forwards or backwards, and at any (sane!) speed, unless someone puts the brakes on.

Finally, if there is any lift also being provided by the plane's engines encouraging air to flow past the wings, as some posters appear to think, this is more by accident than design, especially as most jet engines' exits (for example) are not in front of the main wings, anyway, and this would have more effect on the tailplane, if anywhere at all.

I hope this helps to clarify the position.

Bob.
 
Hi sss,
Well .... you did ask ..... I was compelled to give you an answer.

Hi rfbrw,
If you stopped watching our politicians you'd see that some things do work in Canada. 😀 Besides, it's not that cold here - except today.

-Chris
 
anatech said:
Okay, let's look at the last bit.

ie, the wheels do not rotate. Have I missed anything?
Yes. The statement is ambiguous. The wheels' rotation is, well, a rotation, but the conveyor belt's surface is moving linearly, thus whether or not they are moving in the same direction depends on which point of the wheel you are looking at, e.g. the top is moving forward, thus the conveyor must move back, or the bottom of the wheel is moving back, thus the conveyor is moving forward (although in that case the wheels aren't rotating at all, and so the conveyor belt isn't really moving in the same direction any more).

If instead you take it to mean that the conveyor belt as a complete loop is going round in the opposite direction to the wheel then the surface of the conveyor must be moving backwards.

None of those leaps out immediately as being more correct than the others.



rfbrw said:
In that case, the plane will always take off
I disagree. At best, you can say that as the speed of the conveyor approaches infinity, so does the thrust of the engine, and the state of the system becomes indeterminate and nothing really makes sense anymore.
 
anatech said:
Hi rfbrw,
If you stopped watching our politicians you'd see that some things do work in Canada. 😀 Besides, it's not that cold here - except today.

-Chris

Actually, I was thinking aboot the chemistry involved. I was once told the point of salt was to stop the freezing process icing the road. Salt in solution freezes at around -20 C and I've always imagined Canada to be somewhat colder than that.
 
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