OK....I'm trying to calculate the volume of my speaker boxes that I'm building for the heck of it. The box when standing it's tall height of 100", and you looking at it from the side is a right-angle triangle. Dimensions:H=100" W=12" L=20" My guess to the formula was a simple...l*w*h/2 And I get 196.68 L....Is this correct? With the regular l*w*h equation I get, 393.36L. Here's my thinking...Take the volume of the rectangular prism that is created by two speakers of right-angles and divide that volume by two. It seems right to me.😕
Your calculations are correct if the shorter sides are 12" and 20" in the right angle triangle. Just remember that those are external dimensions from what you say and given 1" material you would come closer to 144 l which is quite different from 197 l.
/UrSv
/UrSv
Oh yeah, I always forget about that part! With stuffing here and there, I'm guesstimating about 139L.
When you caculate the volume substract bracing, port(if any) and driver space. NOT the stuffing. Stuffing is actually making the box appear bigger to the driver, dont ask me how
Keld
Keld
1. This sub will be used for some Party action in my friend's backyard. He wants some *** kickin' bass... Any ideas on how to go about this? More drivers help, right? Watts does too, but we'll base it on a100W RMS amp right now because if you can't make a low-fi driver sound like mid-fi than you're not a good engineer.
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