BOSOZ:
I would like a balance control. However my skills in electronics are poor, and I'm not sure if I can manage to implement this circuit at output p4 without risk of higher output impedance:
http://sound.westhost.com/project01.htm
...so I though off using an alternative (my Bosoz is unbalanced only):
1. Use my two-channel attenuator 5K @P4 as master volume.
2. Use two one-channel 10K pots @P1 as input gain, thus being able to adjust balance.
The reason for this is that I prefer only one master volume control (P4).
Please comment.
I would like a balance control. However my skills in electronics are poor, and I'm not sure if I can manage to implement this circuit at output p4 without risk of higher output impedance:
http://sound.westhost.com/project01.htm
...so I though off using an alternative (my Bosoz is unbalanced only):
1. Use my two-channel attenuator 5K @P4 as master volume.
2. Use two one-channel 10K pots @P1 as input gain, thus being able to adjust balance.
The reason for this is that I prefer only one master volume control (P4).
Please comment.
promitheus, thanks for the info 🙂
You use 10K linear as bal and 10K linear as vol?
Which value for R did you use to get 5K total?
Did you use the switch?
You use 10K linear as bal and 10K linear as vol?
Which value for R did you use to get 5K total?
Did you use the switch?
An externally hosted image should be here but it was not working when we last tested it.
I only have volume control. The problem is i forgot what resistor I used and it´s not so easy to see anymore.
I will take a look later and tell you.
To make it balanced I use a system I bought from www.thel.de to control 2 stereo pots with mechanical junction.
I will take a look later and tell you.
To make it balanced I use a system I bought from www.thel.de to control 2 stereo pots with mechanical junction.
For output P4 with balance control I've decided to make the above circuit using:
Volumen: 5K log stepped attenuator
Balance: 10K lin pot
R = 0,47 * 5K ~ 2K32
Volumen: 5K log stepped attenuator
Balance: 10K lin pot
R = 0,47 * 5K ~ 2K32
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