Hi,
I'm trying to build this design:
http://www.shine7.com/audio/pa100.htm
I've realized that it doesn't have a volume control potentiometer and i want to add it.
How can i do this?
Is it correct to connect both R2 and R7 to the middle of the potentiometer? Then, one side to ground the other to the RCA In filter (R1-C1) ¿?
Thanks a lot !
I'm trying to build this design:
http://www.shine7.com/audio/pa100.htm
I've realized that it doesn't have a volume control potentiometer and i want to add it.
How can i do this?
Is it correct to connect both R2 and R7 to the middle of the potentiometer? Then, one side to ground the other to the RCA In filter (R1-C1) ¿?
Thanks a lot !
J1 Pin1 connects to pot wiper.
J1 Pin2 connects to pot return (bottom).
RCA pole connects to pot input (top).
RCA barrel connects to pot return.
J1 Pin2 connects to pot return (bottom).
RCA pole connects to pot input (top).
RCA barrel connects to pot return.
a very simple way is...the middle pin of the common 3 terminal pots is where u have take the input to your amp..
2 pins remain....to one of them connect your amp and the input signals ground
To the one remaining pin..connect the signal from the input source.
Only one rule applies, the middle pin is the pin from which you have to take the signal to the amp..
The pot will work even if you exchange the other two pins ( 1 & 3 ) positions but it's direction will change from Clockwise to anticlockwise.
2 pins remain....to one of them connect your amp and the input signals ground
To the one remaining pin..connect the signal from the input source.
Only one rule applies, the middle pin is the pin from which you have to take the signal to the amp..
The pot will work even if you exchange the other two pins ( 1 & 3 ) positions but it's direction will change from Clockwise to anticlockwise.
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When choosing a pot, does it need to be an effect pot that handles xx watts or is a normal pot adequate when used on input signal?
Also what decides whether to use a log or a linear pot and which ohmic value you need?
Also what decides whether to use a log or a linear pot and which ohmic value you need?
u don't need too much power handling capacity , most pots are rated around 0.25W, generally a log taper is used.
Loudness increases, I mean dB is a logarithmic measure and human ears also perceive loudness change in logarithmic fashion ( in theory...).
A linear taper would work far too abruptly..a little turn of the knob would blast the hell out of you..
Loudness increases, I mean dB is a logarithmic measure and human ears also perceive loudness change in logarithmic fashion ( in theory...).
A linear taper would work far too abruptly..a little turn of the knob would blast the hell out of you..
keep the pot resistance as low as all your sources are able to drive.
As a starter try comparing 10k to the specifications for minimum load resistance, of what you might want to connect to it.
If the power amp is also low in input impedance (Zin<20k) you have a problem that a pot alone is unlikely to solve.
As a starter try comparing 10k to the specifications for minimum load resistance, of what you might want to connect to it.
If the power amp is also low in input impedance (Zin<20k) you have a problem that a pot alone is unlikely to solve.
AndrewT
My amp says RIN Input Impedance min. 43kΩ nom. 50kΩ max. 57kΩ
Does this mean I should take a 50kΩ pot or should I somehow take into account the resistance from the source also?
My amp says RIN Input Impedance min. 43kΩ nom. 50kΩ max. 57kΩ
Does this mean I should take a 50kΩ pot or should I somehow take into account the resistance from the source also?
Hi Havoc,
a 10k pot will work with your Rin=50k, but you must keep the cables short. That places the volume control near the amplifier. If you can operate like this then OK.
Now check all the sources that may need to drive the 10k pot.
Are they able to do this?
a 10k pot will work with your Rin=50k, but you must keep the cables short. That places the volume control near the amplifier. If you can operate like this then OK.
Now check all the sources that may need to drive the 10k pot.
Are they able to do this?
How do I check this if I plan to use both Mp3 players, dvd players etc. with my amp? I haven't got access to in depth information about the players.
As I don't know how you deduce that 10K is fine could you elaborate (nooby in the other end 😉 ).
I would have thought that i should take a 50K pot at that fits the RIN nom. value?
As I don't know how you deduce that 10K is fine could you elaborate (nooby in the other end 😉 ).
I would have thought that i should take a 50K pot at that fits the RIN nom. value?
u can use a 47k pot..that's a fairly common value and ur mp3 player should be easily able to drive it..since it should have been designed to drive 32ohm headphones.
a 47k or 50k pot has a maximum output impedance of approximately 12k.
Feeding that source impedance into the RF filter that is part of the power amp and the additional capacitance of any interconnect cables will move the RF filter down into the audio range.
The high value pot becomes a variable treble filter.
For 50k input impedance do not use a pot higher than 20k and preferably less than or equal to 10k.
If I were using an unbuffered pot, I would go to 5k.
And make sure my sources could drive that 5k load by adding buffers to any source with an inadequate output stage.
Feeding that source impedance into the RF filter that is part of the power amp and the additional capacitance of any interconnect cables will move the RF filter down into the audio range.
The high value pot becomes a variable treble filter.
For 50k input impedance do not use a pot higher than 20k and preferably less than or equal to 10k.
If I were using an unbuffered pot, I would go to 5k.
And make sure my sources could drive that 5k load by adding buffers to any source with an inadequate output stage.
Agree ...In fact any pot is going to have an effect on sound quality and it will change according to the pot resistance... a DC operated volume control or a specialist volume chip is the only solution..
AndrewT said:
I should have phrased it..only two solutions I know of ....I would be happy to learn better techniques to do so..
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