I wonder if it is possible to omit the inductivity of 1.5mh if I take two C's in line with 8 ohm resistor in between forming a
C R C network
Is it then 12 db, too? Effectively its said to be 18db slope but from the part count its like a 12 db filter
C R C network
Is it then 12 db, too? Effectively its said to be 18db slope but from the part count its like a 12 db filter
I experimented with Zobel creation for a piezo tweeter, assuming that the tweeter can be modeled as a pure 0.1µF capacitance. (That is the model most often mentioned in the literature.) I found that it's pretty easy to Zobel a piezo under that assumption, see attached.
I have not tried this in real life; this is entirely SPICE simulation.
Assumptions: L1 was selected to resonate at 25kHz with the 0.1µF piezo. R1 was selected for flattest magnitude and phase values. R2 was selected such that the impedance magnitude at 15kHz was exactly as specified.
I have not tried this in real life; this is entirely SPICE simulation.
Assumptions: L1 was selected to resonate at 25kHz with the 0.1µF piezo. R1 was selected for flattest magnitude and phase values. R2 was selected such that the impedance magnitude at 15kHz was exactly as specified.
Attachments
Zobel helps present a more benign impedance to the amplifier. This makes it easier to design the crossover network needed by the driver, among other things. In the example that I presented, the crossover could be designed using textbook equations for a pure 4 ohm resistance.
In this case it isn't much different than a simple parallel resistor; just a little better phase response. I just had a little time on my hands, and felt like experimenting.What is the benefit of a Zobel ?
is it making the impedance more linear than a resistor alone?
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