Hello all,
I'm looking for some help determining if the N rank 2sk68a (IDSS ~ 6 mA) will be an ok substitute for the L and M rank parts originally supplied in the Kenwood KA-9100
I will attach photos of the circuits with one being the phono input and the other being the control amp input.
I am also hoping that this issue will help me understand JFET's and JFET circuits better so please understand if I make assumptions in what I write here that are totally wrong.
first the phono circuit that specifies L rank 2sk68a's that are currently 2-2.5 mA IDSS parts.
I can only guess how the circuit would react to the higher IDSS parts. But it would seem that with the given values on the schematic, the current flow through the JFET would increase roughly in proportion to the difference in IDSS between parts. However, since the circuit is biased with fixed resistors, the operating points of the circuit would shift. Can anyone explain or model what would happen here, using the higher IDSS parts?
Same here for the control amp input: where they used different ranks within the differential pair although based on the circuit it makes sense why that might be required, I can't say exactly why.
I'm looking for some help determining if the N rank 2sk68a (IDSS ~ 6 mA) will be an ok substitute for the L and M rank parts originally supplied in the Kenwood KA-9100
I will attach photos of the circuits with one being the phono input and the other being the control amp input.
I am also hoping that this issue will help me understand JFET's and JFET circuits better so please understand if I make assumptions in what I write here that are totally wrong.
first the phono circuit that specifies L rank 2sk68a's that are currently 2-2.5 mA IDSS parts.
I can only guess how the circuit would react to the higher IDSS parts. But it would seem that with the given values on the schematic, the current flow through the JFET would increase roughly in proportion to the difference in IDSS between parts. However, since the circuit is biased with fixed resistors, the operating points of the circuit would shift. Can anyone explain or model what would happen here, using the higher IDSS parts?
Same here for the control amp input: where they used different ranks within the differential pair although based on the circuit it makes sense why that might be required, I can't say exactly why.