bridge rectifier

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i am a bit confused, just as i thought i was getting to understand about how these work.
in the picture attached are two diagrams.
figure 1 shows a snap shot of the one in the amp im working on
figure 2 shows, what i assume is a typical set up of one of these guys,


what i am confused about is on figure 1 it shows 2 possitive supplies going to the rectifier, where as figure 2 shows it to be +/- to each of the terminals.


am i looking at this incorrectly, or is it the one on my board isnt doing what i think it is?


when the rectifier is on the board there is a dead short between the + and - legs, but not when it is off the board, as i checked it, so there is obviously something a miss elsewhere which i will have to look for, but i just dont understand the diagram.



many thanks
 

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The markings on figure 2 are misleading. The + and - should not be where they are.

Fig 1 is essentially the same configuration but with a centre tap in the mains transformer. This is used to provide a dual or split supply.
 
I borrowed these screenshots from youtube... Not my work, but explains how bridge rectifiers works fairly well/ simple. Just imagine Red leaving the source through the rectifiers, through the load, and blue returning to the source(through the rectifiers). They switch direction with the swing.

Cheers,
Tim
 

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I borrowed these screenshots from youtube... Not my work, but explains how bridge rectifiers works fairly well/ simple. Just imagine Red leaving the source through the rectifiers, through the load, and blue returning to the source(through the rectifiers). They switch direction with the swing.

Cheers,
Tim
thats great thanks.there are so many items out there that look simlar, its hard to decide whats right,


cheers, paul
 
Yes, I found it frustrating at first as well.

Just imagine that both Grounds are connected by a wire (they are electrically connected through a common ground), and the picture I sent shows it in the best way I understand it.

Each rectifier path of a full wave bridge sends out a positive half wave signal, regardless of input polarity . If you only used a half wave bridge, the voltage would have gaps while the source is "reversed", as it wouldn't be able to pass the reverse polarity through the diodes.