Using valve heater as load resistor. Would that work?

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I am pretty sure someone already did this before. For low power class A SE resistor loaded amplifiers - could one use the cathode heater winding instead of the resistor?

For example, EL34 needs 6.3 V for 1.5 A heater current. Two in series could be used with 24 V power supply and 1.5 A bias current. The main point would be that the tubes would dissipate the heat naturally and there would be no need for a high power resistor and a heatsink. The bonus would be the looks of glowing tubes.

EL34 is a common tube and if you have a friend guitarist with a Marshall amp, you could just use the tubes that would go to trash after re-tubing, because the heater winding is usually still fine even when the tubes are worn out.

Is this something that would work? The intended use of this amp would be for horn loaded compression drivers, maybe even just a MOSFET follower at the output of the DSP. No more than a few Watts is needed there.

Is that idea worth trying or is it a complete nonsense?
 
So you want to use a highly nonlinear resistor to set the bias for the output tube(s)? That could work, but probably not very well. I'm reminded of a buddy of mine who "repaired" a TV by using a clothes iron as a power resistor until he could source the replacement resistor. It worked, but it wasn't a production solution.

As others have pointed out, the cold resistance of the filament is pretty low. This means your output tube will draw lots of plate current until that current heats up the filament of the "bias tube". That'll be really hard on the output tube. It would also likely cause the output transformer to saturate, which further stresses the output tube.

Power resistors are not that expensive... Use one. Or if you don't like power resistors design something with fixed bias.

Tom
 
True... but think of the power wasted. I think Nelson has an amp using a bulb as load resistor for a single ended output stage and so using heaters kind of seemed a cool idea if the values work out.
 
Oh, I see. So a Class A, resistor biased, single-ended MOS output stage with a tube filament instead of the resistor? That MOSFET will go poof as soon as the power is turned on due to the cold resistance of the filaments. Even if by some miracle it doesn't the nonlinearity of the filament resistance will wreck performance.

I suppose one could design a circuit that pre-heats the filaments until they reach their nominal 'hot' resistance and then switches over to the MOSFET before the filaments have a chance to cool off. A simple relay with a delay circuit would probably work well enough. Or one could get fancy and measure the current through the filaments and switch over once it reaches 95% of the steady-state value. That starts to approach the infamous 10 lb of sh** in a 5-lb bag pretty quickly though and still leaves you with a highly nonlinear load resistor. But hey... Maybe the added nonlinearity adds something-something to the sound. It'd be quick to try in a prototype.

Another thing to consider is that the resistance of the filament/heater is not tightly controlled from tube to tube, so the bias of that MOS output stage may vary all over the place depending on which tubes are stuffed into the bias circuit.

Tom
 
Tube heaters are different from light bulb filaments....one is almost immediately white hot, and the other warms up to red heat.
I agree, use a load resistor, 10 to 50 cent part here in India for up to 5W rating. And light the filaments separately if you want that retro look.
 
As pointed out further up. Tubes (ie cathode to anode) vary quite a bit in manufacture. I would suspect the distribution of heater resistances would be even wider. This is before we get to any in operation linearity or other discussions! The same is true for matching two light bulbs used in two oscillators.

Thinking about this more - I probably wouldn't. It may be better having some old 1920s steampunk lightbulbs for effect but leave the real work to resistors.