difference measuring DC offset with and without source

I have built a headphone amp with an bipolar opamp for voltage gain and another as a buffer. Nothing special I think but it has no input capacitors because I want to test it without.

It works but when I measure DC offset at the output without a source I get 77mV.
When I connect 10k at the input I measure 5mV.

Why is this? Without anything connected at the input I can imagine it picks up mains hum and such but then I would expect more AC than DC at the output.

Can anyone explain this to me?

Thanks,

regards,

Cor
 
What's the input impedance / resistance? It would seem to be on the order of 150k...

Without a source, opamp input bias current will flow through this resistance and create a finite voltage drop. Same goes for the resistance on the other leg, which is likely to be substantially lower. This leaves a net voltage offset, which is then amplified by DC gain - I have a hunch this is greater than unity in your case.

That's about as much as I can say without a schematic.
 
The input impedance is 100k, the other leg has 2k to ground. The gain is 5.1x. So your explanation is probably right.

Usually I measure the DC offset with input connected to a source or the input connected to ground but not this time.

Now I now why this happens, learned something, thanks!

What's the input impedance / resistance? It would seem to be on the order of 150k...

Without a source, opamp input bias current will flow through this resistance and create a finite voltage drop. Same goes for the resistance on the other leg, which is likely to be substantially lower. This leaves a net voltage offset, which is then amplified by DC gain - I have a hunch this is greater than unity in your case.

That's about as much as I can say without a schematic.
 
It will be no problem because when the amplifier is in use it has a 10k potmeter at the input and it is connected to an input source.
I predict the DC offset will be minimal then. But thank you for your suggestion.

Input bias current.

Try to put jfet-based opamp at the input position or compensate source resistance at the inverting leg of the opamp.