How can calculate the voltage divider to attenuate 0.5dBs, my tube preamp have an input impedance of 50K or 100K because I use two separate volume pots. Using L-Pad calculator:
50K L-Pad
R1 2796.96
R2 843828.8
100K L-Pad
R1 5593.91
R2 1687657.61
Can I use these values?
TIA
50K L-Pad
R1 2796.96
R2 843828.8
100K L-Pad
R1 5593.91
R2 1687657.61
Can I use these values?
TIA
To calculate the values you use circuit theory and algebra, or find an online calculator (as you seem to have done).
Having obtained the values, I don't understand your question about using them. Note that 0.5dB is could be an inaudible change.
Having obtained the values, I don't understand your question about using them. Note that 0.5dB is could be an inaudible change.
or just add a single resistor in the feed to each channel.
For a pot the required added resistance would be
{1 / [inv log (0.5/20 +-)] -1}* pot value
[1.05925-1]*50k or 100k
2963r for 50k or 5925r for 100k.
But can you hear a -0.5db reduction?
For a pot the required added resistance would be
{1 / [inv log (0.5/20 +-)] -1}* pot value
[1.05925-1]*50k or 100k
2963r for 50k or 5925r for 100k.
But can you hear a -0.5db reduction?
I don't know: is the RMMA measurement, I added the resistor and now I will listen, I come back with the result.
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Hi,
I don't understand it either. Do you want to attenuate a driver unit in your speaker(s) or do you want to replace the pots in your preamp by a switched attenuator?
If the latter I can't see why one would use such inaudibly fine steps, there's a good chance L to R channel imbalance is already roughly that or worse.
Also when you say you have two pots, do you mean one for each channel and if so you need to know their exact impedance 100K log or 50K log?
Ciao, 😉
I don't understand it either. Do you want to attenuate a driver unit in your speaker(s) or do you want to replace the pots in your preamp by a switched attenuator?
If the latter I can't see why one would use such inaudibly fine steps, there's a good chance L to R channel imbalance is already roughly that or worse.
Also when you say you have two pots, do you mean one for each channel and if so you need to know their exact impedance 100K log or 50K log?
Ciao, 😉
I want to attenuate 0.5dBs in one channel of my tube preamp. My tube preamp don't have volume control inside the box, I'm using in other two boxes one 100K Log and the other one box 50k Log.
GUESS WORK....
Ola,
Assuming these are stereo pots and one channel is miss tracking by 0.5 dB over the entire track??
Adeu, 😉
Ola,
Assuming these are stereo pots and one channel is miss tracking by 0.5 dB over the entire track??
Adeu, 😉
I only want to be sure isn't any difference. Because the rest of the system can increase or cancel the difference.
Hola
Yes are stereo pots, both pots tracking well, the problem is the tubed preamp.
Do you speak Catalan🙂?
I think the OP is doing some experimenting and wants to know that his 2 channels are exactly the same electronically before the rest of the circuitry does it's corrections.
Hello,
Begur is a very nice place like all places in Costa Brava, I'm living in Blanes (South Costa Brava)🙂.
Fins aviat😉
Begur is a very nice place like all places in Costa Brava, I'm living in Blanes (South Costa Brava)🙂.
Fins aviat😉
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