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#1 |
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diyAudio Member
Join Date: Jun 2004
Location: Indiana
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I have mentioned in passing a mini-console project that I am working on. As I am getting ready to start drilling the chassis for the PA section I thought I would post the intended schematic including the preamp section. I am sure that some details will change as I test the results.
The preamp (12AX7 and 12AU7s) will be on a separate small chassis salvaged from a hammond L-101. Power supply will be 5AR4 rectifier with CLCLC filtering. The speaker drivers will be MA CHR-70 (series one) in BR tuned to get solid output down to a bit below 40Hz. One concern is that some subwoofer amps may not be able to adjust crossover down low enough to avoid a boomy bump when trying to integrate with the mains. I may try to add a switchable HP filter to help with that. Comments welcome.
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#2 |
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diyAudio Member
Join Date: Jun 2004
Location: Indiana
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I just realized last night that this won't really cut it for my intended use. The primary input source is an iPod which in my experience has less output voltage than a CDP. I figure maybe 1V peak (1.4V RMS) which is no where near enough to drive this to full output.
It has been suggested to me that using pentode drivers would work better for the shade FB and I should think would also have more gain but I question whether even that would be enough. The preamp section above actually has a gain of slightly less than unity. I suspect that the easiest solution is to drill out an unused 7 pin socket on the preamp chassis and install an additional 9 pin socket which I could use for an additional gain stage (say 6N1P) immediately after the tone control section.
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If We The People refuse to hear the truth we will be ruled by liars. |
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#3 |
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diyAudio Member
Join Date: Jun 2007
Location: Holt, Norfolk
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Since your tone control is a negative feedback type you don't really need to drive it from a very low source impedance like a cathode follower. So an alternative would be to change the first stage into a common cathode gain stage.
Cheers Ian
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Ian Last edited by ruffrecords; 15th February 2011 at 04:59 PM. Reason: spelling correction |
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#4 |
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diyAudio Member
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Opposite, actually... Parallel feedback makes it look as if it is loaded on a virtual ground.
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If I disappear suddenly, that means I finally created a time machine and pushed wrong button that brought me to Stalin's Russia. In any experiment any result is the result. Even if it is negative. |
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#5 | |
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diyAudio Member
Join Date: Jun 2007
Location: Holt, Norfolk
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Quote:
Cheers ian
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Ian |
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#6 |
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diyAudio Member
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Your guess is wrong again. Parallel feedback decreases input resistance. Ref: Ohm's law.
![]() Or, here is the picture I drew for students many years ago, to explain them feedback basics: hope it helps... www.wavebourn.com • View topic - Feedback basics Edit: similarly, U8 (6N1P) is loaded not only on 47K in parallel with 220K, but also on 270K/8 (I assume gain of KT-88 stage is 8). Plus, since gain of KT88 is non-linear, it is loaded on non-linear resistance.
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If I disappear suddenly, that means I finally created a time machine and pushed wrong button that brought me to Stalin's Russia. In any experiment any result is the result. Even if it is negative. Last edited by Wavebourn; 16th February 2011 at 12:21 AM. |
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#7 |
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diyAudio Member
Join Date: Jun 2007
Location: Holt, Norfolk
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I agree about U8 but I am referring to the NFB around U2 the 12AX7. Referring to your NOOBs guide to NFB that you so thoughtfully provided a link to, what we need to identify is the value of R1 in your little op amp circuit below, as that is effectivekly what defines the input impedance in this instance.
http://www.wavebourn.com/images/op_amp_neg.gif Cheers Ian
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Ian |
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#8 |
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diyAudio Member
Join Date: May 2007
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Although the input impedance of the tone control is reasonably high, as ruffrecords says, it does vary with both frequency and tone control position. At centre, LF Z is 181K (56K+125K), HF it is 43K (56K||181K). This is why it needs a low impedance drive. However, I would have thought that the anode impedance of a common-cathode 12AU7 is low enough to suffice - after all, this is not hi-fi!
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#9 | |
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diyAudio Member
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Quote:
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If I disappear suddenly, that means I finally created a time machine and pushed wrong button that brought me to Stalin's Russia. In any experiment any result is the result. Even if it is negative. |
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#10 |
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diyAudio Member
Join Date: May 2007
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Yes, I agree that the tone circuit is loaded by a virtual ground. The issue is input impedance. This is high, but unfortunately too variable.
Note that the high value resistors from sliders to grid do not raise the input impedance, as the grid is not the virtual ground. The sliders jointly form the virtual ground. The high value resistors merely reduce the open-loop stage gain, and isolate the two pots from each other. |
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