Yes, for 2500W/4R you need 100V RMS at the output, and +/-140V DC rail voltage in 2 or 3 step.
Regards
thank you for the answer sir...
1 this means if i have a class aB amp with +/-100v psu, i would get maximum of 1250w at 8ohms disregard of all the losses i may have...
i just dont know how much efficiency class aB amps have...
2 in h class amps, i notice that adding step drivers to a class Ab amp adds more power to it,just like b500 and h900, how does step drivers help in adding more power to an amp???
3 are there possible ways{circuits} for step drivers that uses bjt's and easy to find ic's instead of mosfets and some rare ic's???..
thank you sir...
sorry for all these questions...for i am still in the process of learning...
regards...
ees...
With +/-100V rail voltage power will be 625W/8R not 1250W.
CREST PRO 8001 use only BJTs for class H step driver.
Regards
sir...
how did you arrive to that answer???...
i was completely wrong in my estimate...
thanks...
Divide peak voltage by the square root of 2 (1.41....). In your example 100/sqrt2 (100/1.41).
sir i did not not arrive to the same answer as sir apex came...but abit closer...
i arrive at 628w...
i use
{(100/1.41)*(100/1.41)} / 8 = 628w
where was i wrong???...
ok sir thanks...
now i arrive at hte same answer as sir mile had...
625w of power...
thanks a lot..
ees...
