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6th September 2004, 09:32 PM  #21  
diyAudio Member
Join Date: Oct 2003
Location: The Lab

Quote:
And since 1/3 x 3 kHz is 1 kHz, isn't then 1/3 x 3f the same as 1 x f ? So 1 x 1f + 1 x 1f + 1 x 1f ... or just infinity f Did i miss something? 

6th September 2004, 10:27 PM  #22 
diyAudio Member
Join Date: Apr 2003
Location: Cambridge

I think what it should be is a bit more like the thing below (try typing that into vbulletin) which holds true of all repeating signals, not just square waves (they just hapen to have much larger percentages of the higher harmonics than some other signals like sine, or triangle waves).

6th September 2004, 10:37 PM  #23  
diyAudio Member
Join Date: Nov 2003
Location: Saskatoon

Quote:
Lars, what he meant was 1A x 1f + 1/3A x 3f + 1/5A x 5f ... etc, where A = amplitude. 

6th September 2004, 10:55 PM  #24 
diyAudio Member
Join Date: Sep 2004
Location: Toronto, Ontario

Who says Math cant be fun ?
Fourier Series of a Square wave
∞ x(t) = ∑ (4V/ k* pi) sin (kwt) V = amplitude k =1 Where k is odd So basically you get the fundamental w (angular freq) and odd harmonics decreasing at a rate of 1/k w = 4V / pi 3w = 4V / 3pi 5w = 4V / 5pi and so forth until finity or you stop caring 
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