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|12th January 2019, 09:51 PM||#1|
Join Date: Oct 2018
4th-Order filter = Ratios of two 2nd-Order filters?
I recall reading an article that described a 4th-Order filter in terms of two cascaded 2nd-Order filters with specific ratios of f3 and Q.
It looked something like this. The numbers aren't exact, just there to illustrate the point.
4nd-Order Filter with f3 and Q.
2nd-Order Filter 1
f1 = 0.89 * f3
Q1 = .765 * Q
2nd-Order Filter 2
f2 = 1.13 * f3
Q2 = 1.25 * Q
Is it really this simple? If so, is there a table of these ratios?
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