Hello everyone,
please pardon my english knowledge, which is a little bit better than not good at all.
I have a probably very simple problem with the JAB's (JAB3+, JAB4, JAB5) in general. I have had several JABs fail over the years and I don't understand why. First I thought, coincidence or application error, meanwhile I think - that can't be, the boards must be able to stand what I do there.
In all cases the boards were supplied with voltage within the specs by a battery. The wiring looks like this:
The only board that ran without errors had a LM317 connected in the supply, so that max. 24V arrives at the board. But this could not supply the necessary current for larger volumes, since this (I was not careful while selecting the LM317) permitted only Ioutmax = 500mA.
Can it be that by my circuit (ground board permanently to Bat-Minus) when switching off the board the potential settles to the positive terminal on Bat-Minus, incl. capacitors of the board and then when switching on a current arises, which the board can not withstand? Shouldn't the board be designed to withstand that?
How do you do it, do you all disconnect both terminals with a switch?
Best regards,
Frederik
please pardon my english knowledge, which is a little bit better than not good at all.
I have a probably very simple problem with the JAB's (JAB3+, JAB4, JAB5) in general. I have had several JABs fail over the years and I don't understand why. First I thought, coincidence or application error, meanwhile I think - that can't be, the boards must be able to stand what I do there.
In all cases the boards were supplied with voltage within the specs by a battery. The wiring looks like this:
- Battery minus to the ground of the board
- Battery plus via a switch (I tried a relay, too) to plus of the board.
The only board that ran without errors had a LM317 connected in the supply, so that max. 24V arrives at the board. But this could not supply the necessary current for larger volumes, since this (I was not careful while selecting the LM317) permitted only Ioutmax = 500mA.
Can it be that by my circuit (ground board permanently to Bat-Minus) when switching off the board the potential settles to the positive terminal on Bat-Minus, incl. capacitors of the board and then when switching on a current arises, which the board can not withstand? Shouldn't the board be designed to withstand that?
How do you do it, do you all disconnect both terminals with a switch?
Best regards,
Frederik
You usually need a simple switch in any of the battery terminals to stopcurrent to flow. No need for both conductors to be switched. There must be other issue or cause for the failed units.