Can someone help me undertsand how the SE input works on a 2ch BTL TPA3255? Are inputs A and C inverted to feed inputs B and D?
Hi,
Not sure your question makes sense.
For the BTL mode, then the input will have to be differential, between input A and B, and input C and D.
Examining the datasheet Functional Block diagram on page 15, the inputs are non-inverting. If you apply a single ended signal to input A, and ground input B, then the output power will be as per single ended operation, essentially half of the BTL output power.
Figure 29 on page 22 indicates that you have to supply the differential signal, so the inputs are not internally inverted to provide BTL operation.
Regards,
Shadders.
Not sure your question makes sense.
For the BTL mode, then the input will have to be differential, between input A and B, and input C and D.
Examining the datasheet Functional Block diagram on page 15, the inputs are non-inverting. If you apply a single ended signal to input A, and ground input B, then the output power will be as per single ended operation, essentially half of the BTL output power.
Figure 29 on page 22 indicates that you have to supply the differential signal, so the inputs are not internally inverted to provide BTL operation.
Regards,
Shadders.
I found a post that said on some boards with a SE jumper, the input is run through a voltage divider and half fed to the non-inverting input A and the other half to input B which is inverted using the other half of the dual op-amp. That should give full out power. I don't know if this is true for the board I have though.
Hi,
The TI TPA3255 evaluation module i believe has a single ended to balanced circuit to drive the IC. What ever board you have, if it has the same capability, then you don't have an issue.
Regards,
Shadders.
The TI TPA3255 evaluation module i believe has a single ended to balanced circuit to drive the IC. What ever board you have, if it has the same capability, then you don't have an issue.
Regards,
Shadders.