Cheap and cheerful. Make a bi-polar cap from two series back to back electrolytics of equal value. Wire either plus to plus or minus to minus. You would have to experiment with values. Try 470uf for starters and work down from there. 63 volt caps should cover it.
or add a horn tweeter to get more high end.
a 4 inch driver depending on type and what type enclosure it's in would be bare minimum for a PA application. if you could give a little more info as to what your goal is it may get you more "guidance".
a 4 inch driver depending on type and what type enclosure it's in would be bare minimum for a PA application. if you could give a little more info as to what your goal is it may get you more "guidance".
i have a metal column speaker of speaker 6 by 4 but it is producing more bass. i want to reduce it.
It is a common value. Two in series will give 470/2 or 235uF. That would give a -3dB point of around 170Hz with a 4 ohm load. Your speaker impedance will vary from 4 ohms but it gives you an idea what it does. If you need even less bass then try two 220uF caps.
if it's a manufactured column speaker that was meant for a 70 V system there may be a matching transformer that's in the way.
You have a series circuit of 235uF and 4 ohm. The time constant of that combination is 235uF * 4 which is 0.00094 seconds. The cut off frequency is 1/2 (pi*t) which is 170 (Hz)
Must admit I've never seen it worked out that way before 😀
I just calculate the reactance of the capacitor.
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