I have seen several potentiometer breakout boards such as this one:
I am little confused, though, because I don't see a trace connecting the ground pins of the potentiometer to the holes labeled IN - G or OUT - G.
What am I missing?
Sorry if this is another silly question!
I am little confused, though, because I don't see a trace connecting the ground pins of the potentiometer to the holes labeled IN - G or OUT - G.
What am I missing?
Sorry if this is another silly question!
There is a ground plane on the top side, and the two pot ground pads go directly there.
So do the output grounds (look at the thermal reliefs).
Thank you very much!
Ah, ah, I am such a noob.
I had to look all of that up!
So, the top side is entirely conductive and joins all the ground pads. (the ground plane)
The bottom side has individual traces to establish the rest of the required connections.
And thermal relief pads are described there: https://en.wikipedia.org/wiki/Thermal_relief
They are the weird-looking pads that connect to the surrounding copper. (ground plane of the top layer in this case)
Like in this example:
Did I get it completely right?