Im going to make this real short,
1. If i connect 2 woofers in parralell. and pump 100 watts into both of them. does each woofer get 100 watts of power each. or 50 watts of power each.
2. if i connect in series. do they get 50 watts each or 100 watts each.
Thanks.
1. If i connect 2 woofers in parralell. and pump 100 watts into both of them. does each woofer get 100 watts of power each. or 50 watts of power each.
2. if i connect in series. do they get 50 watts each or 100 watts each.
Thanks.
Well both woofers will see the same power IF they are the same impedance. Two 4 ohm woofer in series will be final load of 8 ohms. the effective voltage will split between the two but in a series circuit the current will be constant. therefore the power will be split by two because the voltage is split equally, times the current. since both the voltage across each woofer is the same and the power is too.
In a parellel circuit the effective current would be split but the voltage would be constant resulting in equal power same as above. the only difference is the current would double as the load would now be 2ohms.
In a parellel circuit the effective current would be split but the voltage would be constant resulting in equal power same as above. the only difference is the current would double as the load would now be 2ohms.
WHOA,.,, too complicated
there are two woofers.
both 8 ohm
wired in parralell.
to make 4 ohms
when i pump 100 watts into the bank of woofers.
does each woofer see 100 watts. or 50.
just answer with "100" or "50"
thanks
there are two woofers.
both 8 ohm
wired in parralell.
to make 4 ohms
when i pump 100 watts into the bank of woofers.
does each woofer see 100 watts. or 50.
just answer with "100" or "50"
thanks
Hi Jaden,
your not going to like this answer but take the time to read it and then ask if you need a further explanation.
Two speakers in series will automatically share the power, but because you have doubled the impedance the amp will now only drive about half power into the series combination. This means each speaker will only receive about 25 to 30 watts not 50 watts.
Two speakers in parallel will each receive about 80 to 100 watts but with a poor amp it could be as low as 50 watts each. With badly designed current limiting or fold back limiting, paralleling could reduce the power to almost zero into each speaker.
your not going to like this answer but take the time to read it and then ask if you need a further explanation.
Two speakers in series will automatically share the power, but because you have doubled the impedance the amp will now only drive about half power into the series combination. This means each speaker will only receive about 25 to 30 watts not 50 watts.
Two speakers in parallel will each receive about 80 to 100 watts but with a poor amp it could be as low as 50 watts each. With badly designed current limiting or fold back limiting, paralleling could reduce the power to almost zero into each speaker.
I sounds like you are trying to maximize watts to each woofer. Parrallel will do that if you have an amplifier that can handle the current. Nominal 8-ohm speakers oftem dip below 8-ohms at some point in their intented frequency band. Sometime quite a bit. So you amplifier is going to see them as a single nominal 4-ohm speaker that probably dips below 4-ohms at some point. If you are buying these from some place like Partsexpress or Madisound chech to see if any impedance curve data is available. If you have not bought an amp to go wiith them, make your choice accordingly.
NO I DONT GET IT
OK IF I HAVE 2 WOOFERS
Wired in parrallell.
8ohms + 8 ohms, = 4 ohms.
and my amp puts out 100 watts at 4 ohms.
does that mean each sub recieves 100 watts of power..
or 50?
OK IF I HAVE 2 WOOFERS
Wired in parrallell.
8ohms + 8 ohms, = 4 ohms.
and my amp puts out 100 watts at 4 ohms.
does that mean each sub recieves 100 watts of power..
or 50?
jadenlinkletter said:
Yeah, I know what you mean. With all the obfuscation going on around here it's often hard to get a straight answer. And, watch - someone's going to pipe in and tell me I'm wrong.
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