Quick question: Does the primary impedance of an OPT scale linearly as load on the secondary changes?
In other words: If I connect 8ohm speakers to my 8ohm tap, the primary OPT impedance is 5k - so if I connect 4ohm speakers to my 8ohm tap the primary OPT impedance will drop to 2.5k (4/8=0.5*5000=2500)?
Doing the math for a different scenario:12ohm speakers on the 16ohm taps will result in 75% (12/16=0.75) of 5k = 3750 ohm primary impedance?
Same thing for 3ohm speakers on 4ohm tap?: 3/4=0.75 * 5000 = 3750 ohm primary impedance?
In other words: If I connect 8ohm speakers to my 8ohm tap, the primary OPT impedance is 5k - so if I connect 4ohm speakers to my 8ohm tap the primary OPT impedance will drop to 2.5k (4/8=0.5*5000=2500)?
Doing the math for a different scenario:12ohm speakers on the 16ohm taps will result in 75% (12/16=0.75) of 5k = 3750 ohm primary impedance?
Same thing for 3ohm speakers on 4ohm tap?: 3/4=0.75 * 5000 = 3750 ohm primary impedance?