I want to raise the input gain for my TA2024 amp. From the TA2024 chip manual is says that:
So if i want higher input gain I have to raise AV, right?
If thats true I can do that be raising the RF resistance.
I am asking because I was told to solder a 4k7 resistor over the RF resistor (22k). This should raise the gain. But when i try to calculate the total resistance from the 4k7 and 22k i get a lower value than the 22k ohm. That makes me confused.
Parallel Resistor Calculator R1 + R2 = equivalent resistor R resistance equiv total resistor finder made easy - sengpielaudio Sengpiel Berlin
AV = 12(RF/RI)
where RF = feedback resistor, RI = inverting input resistance. And i guess AV = voltage gain?
So if i want higher input gain I have to raise AV, right?
If thats true I can do that be raising the RF resistance.
I am asking because I was told to solder a 4k7 resistor over the RF resistor (22k). This should raise the gain. But when i try to calculate the total resistance from the 4k7 and 22k i get a lower value than the 22k ohm. That makes me confused.
Parallel Resistor Calculator R1 + R2 = equivalent resistor R resistance equiv total resistor finder made easy - sengpielaudio Sengpiel Berlin
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If thats true I can do that be raising the RF resistance.
Yes. Raise the Rf to increase.
I am asking because I was told to solder a 4k7 resistor over the RF resistor (22k). This should raise the gain.
You have been given wrong advice then. That would dramatically decrease gain (by -12dB or so).
Are you sure you read the advice correctly? Could it be that it said to replace the Rf with a 47K resistor for +6dB increased gain instead?
This was what i was told
Thank you!
But i think you are right about replacing the resistor. I will try that.Solder a 4k7 ohm parellel over the resistor indicated in this picture: http://oi39.tinypic.com/34yckdv.jpg
Thank you!
Seems to me that the person giving the advice does not have the same board version as you perhaps?
The resistor highlighted in that pic seems to be the Rin. Piggybacking a 4K7 resistor on top would indeed increase gain.
The resistor highlighted in that pic seems to be the Rin. Piggybacking a 4K7 resistor on top would indeed increase gain.
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Yes the picture is for another version than the one i have, but i thought it would be the same.
My version is this http://www.sure-electronics.net/download/AA-AB32155V300%20SCH.pdf
By looking at the datasheet i guess that i should change R15 and R21. From what you say they should be higher than the 22k ohm that they are now, right?
My version is this http://www.sure-electronics.net/download/AA-AB32155V300%20SCH.pdf
By looking at the datasheet i guess that i should change R15 and R21. From what you say they should be higher than the 22k ohm that they are now, right?
On your version you either replace the Rf (R15+R21) with a higher value or lower the value of Rin (R18+R22) for example by piggybacking a resistor on top. Either would increase gain.
Saturnus, increasing R15 and R21 would increase the resistance right? Then it would be more difficult for a lower power device to drive the amplifier? I thought, and it worked with my version of the amp, decreasing the total resistance to about 4k ohm would increase the max volume with lower power outputs?
Saturnus, increasing R15 and R21 would increase the resistance right?
Yes, as you should.
Higher resistance of Rf = higher gain
Lower resistance of Rin = higher gain
You probably inadvertently decrease Rin, not Rf.
Oops that may be the case. Rin=RI on the datasheet right? I thought it was R1, the number of the resistor on the board.
Which of the two is better, or is there no difference?
Which of the two is better, or is there no difference?
Oops that may be the case. Rin=RI on the datasheet right? I thought it was R1, the number of the resistor on the board.
Which of the two is better, or is there no difference?
Increasing Rf increases the gain of the amp, and decreasing Rin increases the input as the connected source will see a lower impedance. All things being equal and if board is correctly designed for very low noise floor then the former option would be the better one.
You can do both though if it's a very low output source. Then you can start by replacing the Rf to 47K (I normally recommend 82K) and if that's not enough you take the 22K you removed from Rf and piggyback on the Rin to halve the input impedance. Then the input impedance is still in an acceptable range (10K to 50K is the norm) and the gain is still low enough to limit problems with noise.
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I replaced the 22k ohm Rf with a 47k ohm. I only changed R15 since i only use one channel of the amp. It works 🙂 It required more skill to replace and solder the resistor than i thought.
I read some where that you can't parallel the TA2024. Not like the TA2020 that should be able to do that. I might be wrong.
Edit: If you can parallel the TA2024 then the input needs to be mono, right?
Edit: If you can parallel the TA2024 then the input needs to be mono, right?
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You can't parallel the ta2024, it's already bridged internally
Bridged and parallel are two difference things. It's possible to parallel the outputs if the inputs have identical signals. The output coils act like current sharing resistors because of their DCR. You don't gain anything though unless you use a load with half the impedance.
Bridged and parallel are two difference things. It's possible to parallel the outputs if the inputs have identical signals. The output coils act like current sharing resistors because of their DCR. You don't gain anything though unless you use a load with half the impedance.
Well. You do get something besides better current handling, ie. ability to drive 4 ohm loads. You effectively halve the input impedance and thereby increase the gain. And that was the whole point of the thread.
magnus h, since you're already only using one channel, it's already mono. You just tie the inputs and outputs together, respectively obviously.
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Exhumed a relevant thread rather than make a new one..
Copying the voltage gain formula for TA2024 from first post:
Av = 12(Rf/Ri)
Can i make TA2024 unity gain by making Ri one-twelfth of Rf? Say.. Ri = 10k and Rf=120k. Will it be stable?
Copying the voltage gain formula for TA2024 from first post:
Av = 12(Rf/Ri)
Can i make TA2024 unity gain by making Ri one-twelfth of Rf? Say.. Ri = 10k and Rf=120k. Will it be stable?
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