The Cabasse the Pearl loudspeaker supposedly has a 25 cm woofer built in. Which arithmetically would not fit with the size of the enclosure. How do you trick it so that it all works? Devialet must certainly do it similarly, but don't know my way around.
Can I also use this "technique" for my own loudspeakers?
Can I also use this "technique" for my own loudspeakers?
Cabasse lists the size as
Dimensions
326 x 327 x 323 mm (12,6″x 12,6″x 12,6″)
so no problem fitting a 25 cm driver which from the exploded view seems like a "Walsh" style driver and custom so it doesn't come down to a technique that can be used for other drivers...
Dimensions
326 x 327 x 323 mm (12,6″x 12,6″x 12,6″)
so no problem fitting a 25 cm driver which from the exploded view seems like a "Walsh" style driver and custom so it doesn't come down to a technique that can be used for other drivers...
Not really. The volume is 1.2 cubic feet. Which would actually be enough for a 10 inch loudspeaker at first. However, it must be taken into account that this is the total volume and with a spherical loudspeaker you still need something like a flat surface to install the loudspeaker. You would have to subtract this area from the total volume and then you would be easily under 1.2 cubic feet and mathematically it would not fit again: D
Or am I thinking wrong?
It does fit mechanically. And it's an active speaker with a dsp. Just add the 2+2 and you'll realize it's just got a huge boost on the low end to get away with the small enclosure.
There is no particular rule that a certain size woofer "must" have a specific volume of cabinet to work, many designs use lower than ideal cab volume coupled with EQ to boost the "lost" response back up.
As long as it can physically fit, you can bet that someone will have tried fitting woofers in even smaller enclosures than this.
As long as it can physically fit, you can bet that someone will have tried fitting woofers in even smaller enclosures than this.