Hi all, I have trouble obtaining the original transistors of the attached amplifier. So I want to use equivalent transistors. please tell me which transistors are better for using in the amplifier.
(The original amplifier uses +/-95V rails but I'm going to use it with +/-50V)
For:
MJE15034) TIP41 or 2SC669 ?
MJE15035) TIP42 or 2SB649 ?
IRF510) IRF540 or IRF 630 or IRF640 or IRF730 or IRF740 or IRF840 ?
Best regards
Ermac
(The original amplifier uses +/-95V rails but I'm going to use it with +/-50V)
For:
MJE15034) TIP41 or 2SC669 ?
MJE15035) TIP42 or 2SB649 ?
IRF510) IRF540 or IRF 630 or IRF640 or IRF730 or IRF740 or IRF840 ?
Best regards
Ermac
Attachments
Hi,
All transistors are easily obtainable through regular sources, Digikey, etc.
It's a decent design, but do heatsink adequately.
Cheers!
All transistors are easily obtainable through regular sources, Digikey, etc.
It's a decent design, but do heatsink adequately.
Cheers!
Ermac said:I do know all these parts are common and easy to find... but I can't buy them in my country.😡
Lighten up, angry smiley.. you didn't specify that in your original post 😉
What places are available to you?
Cheers!
Geek said:
What places are available to you?
Cheers!
Only a small local store... don't mind. 🙂
I'll use TIP41/42 instead of MJE15034/35. I named a few IRFxxx; can they be used instead of the IRF510 in this amplifier?
Ermac said:I named a few IRFxxx; can they be used instead of the IRF510 in this amplifier?
I have used IRF 520, 610 and 620 in place of an IRF510 successfully before. I don't see why not for the others 🙂
Cheers!
the irf510 is used as a Vbe multiplier.
In this location a BJT can be used.
A To92 can be glued or clamped to the heatsink.
or inserted into a close fitting hole drilled in the heatsink
or
a To126 device can be used bolted to the heatsink or bolted on top of one of the output devices.
The Vbe multiplier transistor must monitor the temperature of the output devices as closely as possible.
Change the 10k VR to 2k and add a resistor in series with it. Try 160r
If your VR is accidentally set to 0r0 then the maximum voltage from the Vbe multiplier will be ~{2200/160 + 1} * Vbe ~=8.8V
The minimum voltage will be ~{2200/(160+2000) + 1} * Vbe ~=1.2V
this will ensure the FETs turn off at minimum Vbe voltage and turn on at maximum Vbe voltage.
But, I repeat my warning mirrored by others.
You are in for a mighty fright that will be expensive and potentially very dangerous when this amplifier blows up.
Start with something much simpler and much cheaper and of much lower voltage.
In this location a BJT can be used.
A To92 can be glued or clamped to the heatsink.
or inserted into a close fitting hole drilled in the heatsink
or
a To126 device can be used bolted to the heatsink or bolted on top of one of the output devices.
The Vbe multiplier transistor must monitor the temperature of the output devices as closely as possible.
Change the 10k VR to 2k and add a resistor in series with it. Try 160r
If your VR is accidentally set to 0r0 then the maximum voltage from the Vbe multiplier will be ~{2200/160 + 1} * Vbe ~=8.8V
The minimum voltage will be ~{2200/(160+2000) + 1} * Vbe ~=1.2V
this will ensure the FETs turn off at minimum Vbe voltage and turn on at maximum Vbe voltage.
But, I repeat my warning mirrored by others.
You are in for a mighty fright that will be expensive and potentially very dangerous when this amplifier blows up.
Start with something much simpler and much cheaper and of much lower voltage.
AndrewT said:the irf510 is used as a Vbe multiplier.
In this location a BJT can be used.
A To92 can be glued or clamped to the heatsink.
or inserted into a close fitting hole drilled in the heatsink
or
a To126 device can be used bolted to the heatsink or bolted on top of one of the output devices.
The Vbe multiplier transistor must monitor the temperature of the output devices as closely as possible.
Change the 10k VR to 2k and add a resistor in series with it. Try 160r
If your VR is accidentally set to 0r0 then the maximum voltage from the Vbe multiplier will be ~{2200/160 + 1} * Vbe ~=8.8V
The minimum voltage will be ~{2200/(160+2000) + 1} * Vbe ~=1.2V
this will ensure the FETs turn off at minimum Vbe voltage and turn on at maximum Vbe voltage.
But, I repeat my warning mirrored by others.
You are in for a mighty fright that will be expensive and potentially very dangerous when this amplifier blows up.
Start with something much simpler and much cheaper and of much lower voltage.
Would you please tell us why other MOSFETs (eg IRF740) cannot be used?
Kind regards, Ermac
- Status
- Not open for further replies.
- Home
- Design & Build
- Parts
- Help with Substituting Transistors