Equivalence theory

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Joined 2008
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I'm having trouble getting my head around it.

Within a vessel in the absence of a gravitational field, virtual gravity is created by acceleration of the vessel. The speed of light on the other hand, measured between a source/receiver couple on the vessel moving in the 'falling' direction is affected by the average velocity, rather than the acceleration.

Two light signals separated in time take a different length of time to reach the receiver on the accelerating vessel due to the instantaneous velocity at different times, whereas a conventional mass 'dropped' within it will fall as it would on Earth.

How is it that this also happens to light in a situation static to a gravitational field, ie from the top of a tower to the ground?