Hi everyone, I'm a new member, honored to be part of this community of fans.

(I'm Italian, sorry but I use google translate)

I have a technical question to ask you: I have a Berhinger equalizer and I can not understand the operation of its high-pass filter shown in the figure (the section in the blue box), or rather it is not clear to me how to identify the model that determines the order of the filter. From the bottom of my ignorance it seemed to me a 2nd order and calculating the min and max cutting frequencies you get values equal to about 10Hz and 250Hz. On the potentiometer instead 10Hz and 400Hz are indicated and in the description of the command we read: "The LOW CUT regulator establishes the lower frequency of the limit of the ULTRAGRAPH PRO. The high-pass filter (18 dB/oct) is adjustable in a range of 10 to 400 Hz. If this filter is in the 10 Hz position, let the signal pass through without affecting it in the slightest."

Can you help me understand the pattern and determine the formula to calculate the cutoff frequency? Does the 100 Ohm resistor (R176) have anything to do with it?

Thank you very much if you can clarify this point for me.

(the goal is to replace the potentiometer with a switch and resistors to have preset frequencies)

(I'm Italian, sorry but I use google translate)

I have a technical question to ask you: I have a Berhinger equalizer and I can not understand the operation of its high-pass filter shown in the figure (the section in the blue box), or rather it is not clear to me how to identify the model that determines the order of the filter. From the bottom of my ignorance it seemed to me a 2nd order and calculating the min and max cutting frequencies you get values equal to about 10Hz and 250Hz. On the potentiometer instead 10Hz and 400Hz are indicated and in the description of the command we read: "The LOW CUT regulator establishes the lower frequency of the limit of the ULTRAGRAPH PRO. The high-pass filter (18 dB/oct) is adjustable in a range of 10 to 400 Hz. If this filter is in the 10 Hz position, let the signal pass through without affecting it in the slightest."

Can you help me understand the pattern and determine the formula to calculate the cutoff frequency? Does the 100 Ohm resistor (R176) have anything to do with it?

Thank you very much if you can clarify this point for me.

(the goal is to replace the potentiometer with a switch and resistors to have preset frequencies)

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