B+5 to 18V

Hi,

I have a single 12ax7 guitar preamp. 300V for the preamp is provided by a power supply like this: https://www.aliexpress.com/item/1005006302470816.html.
I am adding boost in front of my preamp and buffer after it. Both boost and buffer use OPA134. I want to get 18V from 300V to feed both op-amps. I have attempted to do a resistor divider with 100k and 8.2k resistors. Without load I measure 20+ volts, but with the op-amps on, I get actual voltage like 3 volts on the op-amps. And the 100k resistor gets quite hot.

What is the best way to feed two OPA134 from a 300VDC supply (of course 12ax7 doesn't go anywhere, but the supply should be able to handle it all with no problems)?

Thanks.
 
Because I already have a power supply and to keep the number of parts and footprint smaller? And audio power supply is designed to be quiet, so I just want to use the existing one. I've seen on a JFET boost schematic of Dumble ODS that the transistor is powered from B+5 (using something like 150k and 8.2k resistor and a following 10k dropping resistor). So, I don't think I want something weird, I just need to understand how to do it correctly.
 
How about using a simple dc-dc converter on the 6.3v rail to give +/- 15v. That Ali supplier does this:
€4.50 | 20W +- 5V 6V 9V 10V 12V 15V 24V Positive and Negative Dual Output Power Supply DC DC Step-up Boost-Buck Converter module
https://a.aliexpress.com/_EQ8tfcZ

It is very small and simple to connect and shouldn’t create excessive heat. I haven’t used this myself, but just suggesting a possible solution.
Note that if the opamps don’t draw at least 15ma from each rail, you’ll need a 1K resistor on the psu outputs to 0V to meet the minimum current requirement.
 
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The OPA134 has a quiescent current draw of 4 mA per channel.
Your divider 100 k and 8.2 k passes a current of 300V/108200Ohm = 2.8 mA
Once you connect the Op-Amp that wants to draw 8 mA of quiecent current the voltage collapses.

also, the current draw of the op-amps depends on the output and will change. I suggest kind of regulation for the op-amp supply. either a simple zener diode, a shunt- or a series regulator.

try 8.2k and 560 resistors

Ok, but the 8.2 k resistor will need to dissipate more than 10 W.
also keep in mind that if the 560 ohm shunt resistor is accidentally disconnected or damaged you feed 300 V DC into the op-amp with all sorts of (potentially dangerous) risks at connectors.
 
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You can buy one zenerdiode 22V and a MOSFET IRF740.
The MOSFET can take 400V and should be using a small heatsink.

Then do it like this:
300V to 18V.jpg
 
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You can get SMPS from eBay that take 12V/24V in and produce high voltage, perhaps that's a better arrangement - then you can use a safe certified mains supply to 18V and boost from there. Mains supplies from aliexpress are a risk you should seriously consider avoiding.
 
Hi. If you already have dc 300 v, you can use small adc/dc switch mode adapter. While they designed to rectify ac and wotk from dc inside, they accept dc input too. Just choose one with suitable dc output voltages and add common mode dc filter on 300v input.