Acoustic suspension

Bald mathematical equations after Small (not accounting for variable losses, e.g. leakage, damping etc.) and assuming a voltage source amplifier:

Vb = Vas / ([Qtc'/Qts']^2 -1)
Fb = (Qtc'/Qts') * Fs

Where
Vb = box volume
Fb = box tuning
Qts' = Effective Qts (i.e. Qts + series resistance from wire loop, connectors and as relevant passive crossover components)
Qtc' = Effective Qtc (i.e. as calculated using effective Qts).

If the driver isn't capable of 35Hz in a sealed volume, depending on starting Fs, Qts you may be able to force it lower by adding series R if you don't mind burning up power in the resistors, the increased box size, & the reduced sensitivity that comes with it (along with needing to pay attention to heatsinking / dissipation).

An acoustic suspension design is not technically the same thing as a traditional sealed box, nor a Small type alignment. I'm not firing on all cylinders this afternoon, so speaking under correction, but as I recall the bald alignment was Vb = Vas/3 to obtain the desired air-spring effect, which resulted in a Qtc' equal or greater than 2Qts' and an Fb equal or greater than 2Fs.
 
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What driver?

dave
The driver is a Magnat MG-251, this is a foam surround driver from the 80’s. I’ve had these around for years and thought they may be ideal for a project of this kind.
 

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An acoustic suspension box is sealed. A Sealed box is not necessarily an acoustic suspension.

But given how we model drivers these days, the difference is moot. The difference would be buried in the T/S and we don’t have to worry about the distinction.

Fom plugs in a vent are unlikely to seal the box, just push it toward saperiodic and if the amount is sufficient are converted inrto aperiodic (or close enuff for the purpose)

dave