I'm about to replace the burned out incandescent bulbs with LED's. I've read various articles on the subject, here and elsewhere. My question is this...I've read that the two bulbs are wired in PARALLEL, but it's suggested to replace them with two wide angle LED's wired in SERIES with a resistor on the anode of the "first" LED. Good so far? I've also read that the bulbs were powered with -15v rather than +15v, so the arrangement of resistor/led/led would be installed backwards, correct? That doesn't change where the resistor is mounted, does it? Thanks!
BTW, I received the player with the issue that the door wouldn't stay closed. It would close and then reopen, so it wouldn't play a disc. I boiled the tray drive belt in water for about 15 minutes and now it opens and closes and plays perfectly! I will be ordering a new belt anyway.
BTW, I received the player with the issue that the door wouldn't stay closed. It would close and then reopen, so it wouldn't play a disc. I boiled the tray drive belt in water for about 15 minutes and now it opens and closes and plays perfectly! I will be ordering a new belt anyway.
Two LEDs and a resistor all in series is the most efficient way to wire the circuit. Since all the parts are in series it does not matter the order in which they are wired. The LED cathode should point towards the -15V. Try a 1.2K 1/2W resistor for about 10mA LED current. Change the resistor value up or down as needed to get the brightness you want.
