If you have two different drivers in series, and one is ~4-6dB more sensitive, can you compensate without effecting the other driver?
In my particular case, the two drivers are part of a 1st order low pass filter. The more sensitive driver is 3.7 Ohm, and the less sensitive is 3.8 Ohm.
Thanks.
In my particular case, the two drivers are part of a 1st order low pass filter. The more sensitive driver is 3.7 Ohm, and the less sensitive is 3.8 Ohm.
Thanks.
You could add a parallel resistor across the more sensitive driver, adjusting the crossover
capacitor or inductor to keep the crossover point the same. Not ideal to use two different
drivers in series, though. It could be easier/better to use a separate amplifier for each driver,
depending on the details.
capacitor or inductor to keep the crossover point the same. Not ideal to use two different
drivers in series, though. It could be easier/better to use a separate amplifier for each driver,
depending on the details.
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So that would be a single resistor that connects the + and - of the more sensitive driver? How do you calculate what value resistor?
The most direct way is to add a pot across the more sensitive driver, and adjust for subjectively equal sound output.
Then measure the pot, and add a resistor of the same value in its place. You may need a 5W-20W power rating.
You could calculate a value, but since the drivers are not resistors, it would need trial and error listening adjustment anyway. Start with around 4R, and go higher or lower from there.
Then measure the pot, and add a resistor of the same value in its place. You may need a 5W-20W power rating.
You could calculate a value, but since the drivers are not resistors, it would need trial and error listening adjustment anyway. Start with around 4R, and go higher or lower from there.
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