LED's in the cathode..
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SY
On Hiatus

Join Date: Oct 2002
Location: Chicagoland
Quote:
 Originally Posted by tubelab.com A tiny voltage change on the cathode will affect the bias on the tube causing a bigger than normal change in current through the tube.
Let's throw some numbers at it. We can examine the input stage to a power amp using voltage amp -> split load inverter, since that's where you're likely to have the greatest swing. A 12AT7 is a common choice, so let's go with that. Put 120k on the plate. So to get 20V of swing, the current change is 0.16mA. The input voltage will be something like 0.4V.

Now, one can swamp any current changes in the LED by using my resistor-from-B+-to-cathode trick, but for the sake of discussion, let's not. The AC impedance of a red LED will be on the order of 7R at a "normal" plate current for 12AT7. So the voltage swing across it will be about 1.1mV, which is about 0.25% of the input voltage. If the LED nonlinearity at that tiny current swing were 10% (it's not), we're talking about 0.025% added distortion, which is considerably smaller than that contributed by the tube. The actual number will be even smaller.

If we do my resistor trick so that the LED current is 10mA, the impedance is now 4R. So we've dropped the added distortion by nearly half. And at smaller signal swings, the effect of the LED nonlinearity gets even smaller, as is true with higher plate loads. Thus the crazy-low distortion of my phono stage.
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 9th April 2012, 08:03 PM #22 M Gregg   Account disabled at member's request   Join Date: Jun 2010 Location: UK OK, So how does that compare with a resistor in place of the LED? Regards M. Gregg
 9th April 2012, 08:10 PM #23 SY   On Hiatus     Join Date: Oct 2002 Location: Chicagoland Lower distortion, higher gain, lower output impedance. Compared to bypassed resistor, faster recovery from overload, flat response to DC. __________________ "You tell me whar a man gits his corn pone, en I'll tell you what his 'pinions is."
M Gregg
Account disabled at member's request

Join Date: Jun 2010
Location: UK
Quote:
 Originally Posted by SY Lower distortion, higher gain, lower output impedance. Compared to bypassed resistor, faster recovery from overload, flat response to DC.
What can you say to that?
This has also confirmed my findings with the better drive.

Regards
M. Gregg

Brouilly
diyAudio Member

Join Date: Mar 2009
Location: London
Quote:
 Originally Posted by SY Now, one can swamp any current changes in the LED by using my resistor-from-B+-to-cathode trick, but for the sake of discussion, let's not.
Can you explain this trick please? Do you have a reference somewhere that I can look at?

Thanks

Charlie
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Broke solderer with delusions of grandeur

 10th April 2012, 11:10 AM #26 SY   On Hiatus     Join Date: Oct 2002 Location: Chicagoland I've posted it a few times before (and I notice that it has found a place in the latest edition of Valve Amplifiers); it's pretty self-explanatory, and I don't claim originality. Just run a resistor from B+ to the cathode to get a higher LED current. For example, let's say you have a red LED (1.7V) biasing a 12AX7 stage running 1mA, with a 200V supply. To get the LED to a flatter part of the Vf versus If curve, you might want the LED to have 10mA running through it. We supply the extra 9mA from a resistor, which can be calculated by Ohm's Law- R = V/I = (200-1.7)/0.010 ~ 200/0.01 = 20k. As a practical matter, I haven't seen much difference when the plate loads are reasonably high (i.e., running close to constant current). __________________ "You tell me whar a man gits his corn pone, en I'll tell you what his 'pinions is."
hazard500
diyAudio Member

Join Date: Mar 2012
Location: Melbourne
Quote:
 Originally Posted by M Gregg OK, So how does that compare with a resistor in place of the LED? Regards M. Gregg
You need to bear in mind that the a resistor is not a direct replacement for the LED. A LED is functionally eqivalent to a resistor plus a bypass cap, typically an electrolytic.

So - a resistor (unbypassed) in the cathode provides local feedback and reduces gain. Bypassing resistor with a cathode will retain same quiescent bias point, but will tend to reject signal voltage changes, hence providing a psuedo voltage source - so no local feedback, higher gain but also higher distortion, due to reduced feedback and capacitor non-linearities. A LED mimics the voltage source (assuming small dynamic impedance), retaining the gain of the bypassed resistor, but ditching the yucky electro. So for tubeheads who say that they don't want semi-conductors in their circuits, the options are a battery or an electro bypass cap. A simple unbypassed resistor is NOT equivalent.

 10th April 2012, 11:18 AM #28 Brouilly   diyAudio Member     Join Date: Mar 2009 Location: London Thanks, I look forward to VA4 coming out again so I can read up on it. __________________ Broke solderer with delusions of grandeur
 10th April 2012, 12:23 PM #29 TonyTecson   diyAudio Moderator     Join Date: May 2003 Location: Palatiw, Pasig City i blame it all on SY, now i use only led's on my small tube amp cathodes.... i still do use resistor/capacitor combo on my guitar amps...... __________________ planet10 needs your help: Let's help Ruth and Dave...http://www.diyaudio.com/forums/plane...ml#post5010547[B
 10th April 2012, 01:10 PM #30 TheGimp   diyAudio Member     Join Date: Aug 2009 Location: Johnson City, TN Likewise, I've run 6N1P, 6N2P, 6N3P, and 6N23P with LED bias and current source as anode load and the distortion figures were consistently lower than the equivalent biased resistor load, resistor or resistor and cap in cathode circuit. I used both HP spectrum analyzer and PC with sound-card for distortion measurements and to look at harmonic distribution.

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