Biasing schemes for bipolar transistor circlotrons - diyAudio
 Biasing schemes for bipolar transistor circlotrons
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 16th October 2010, 02:54 PM #1 diyAudio Member   Join Date: Jan 2009 Biasing schemes for bipolar transistor circlotrons My experiments with bipolar transistor circlotron amplifiers are being frustrated because I can't seem to figure out how to get the amplifier to bias properly. With a standard solid state amplifier design, one uses the Vbe multiplier to get a defined voltage at the output devices base and the quiescent current is set by the drop across the emitter resistor, but in trying to set something similar up with a circlotron, I can never get it to work out properly. Any advice or examples would be much appreciated!
 16th October 2010, 03:21 PM #2 diyAudio Member     Join Date: Sep 2006 Basically you first have to understand how the circlotron works. You have two options: let's call them Thevenin and Norton. In the Thevenin case, you have an auxiliary supply referenced to the emitter of the top transistor, feeding the base through a bias resistor. The lower transistor simply has a resistor between base and emitter. The driver transistor is connected between the bases, and diverts a controlled fraction of the bias current from the top transistor to the bottom one. Normally, under quiescent conditions, exactly half of the bias current is passed through the driver. In the Norton circuit, both transistor have identical E to B resistors, and a CCS supplies twice the bias current to the top transistor, and as in the previous case, half of this current is taken by the driver to the base of the bottom transistor. Both approaches are equivalent from a theoretical standpoint, but I find the Norton version much easier to apply practically. Here is a practical example: http://www.diyaudio.com/forums/attac...-unigabuff.gif It is a bit unusual, because it is implemented as a unity gain buffer, but if you make Q4 NPN, it becomes the standard circuit. The current source is Q3, and it has to compensate thermally the output transistors via D1 or D2, the other serving as a self compensation. In addition, this circuit has a servo-controlled Iq via Q5 and Q6, but conventional emitter degeneration is also usable.
 16th October 2010, 04:16 PM #3 diyAudio Member   Join Date: Jun 2008 Location: SoCal Look for a SUMO NINE or NINE+ schematic. It's a solid state circlotron from the late 70s/early 80s. I don't know the details of your amp but maybe you'll get some ideas from the SUMOs. Craig
 17th October 2010, 04:18 AM #4 diyAudio Member     Join Date: Feb 2001 Location: USA Audio amplifier - Google Patent Search In practice the two cathodes are tied together and a variable resistor is returned from the cathodes to ground. __________________ Candidates for the Darwin Award should not read this author. Last edited by djk; 17th October 2010 at 04:20 AM.
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Quote:
 Originally Posted by Elvee Basically you first have to understand how the circlotron works. You have two options: let's call them Thevenin and Norton. In the Thevenin case, you have an auxiliary supply referenced to the emitter of the top transistor, feeding the base through a bias resistor. The lower transistor simply has a resistor between base and emitter. The driver transistor is connected between the bases, and diverts a controlled fraction of the bias current from the top transistor to the bottom one. Normally, under quiescent conditions, exactly half of the bias current is passed through the driver.
Thank you for your reply. I'm a little unclear on how this would work - for example, in the circuit you posted, let's say I remove the bias stabilization circuit consisting of Q5 and Q6 and put in place emitter resistors in each power transistor. In that case the current from the current source is going to zip down through Q3 and through R4, and through Q4 and R5. There's no way to "force" the current to go into the bases of the power transistor. In that case I don't see how one would set a quiescent bias point for the output transistors using such a current source.

 17th October 2010, 08:22 AM #6 diyAudio Member     Join Date: Sep 2006 Part of the current provided by Q3 will go into R4, and the rest will be diverted by Q4 to R5. When the circuit is properly adjusted, the voltages across R4 and R5 will be equal and just sufficient to reach the Vbe of the output transistors. The quiescent current will be set by the common current generator Q3, which is why it has to be thermally coupled to the output transistors. Q4 manages the way the total current is shared between the output devices: if it conducts less, Q2 will be completely off, and the excess current will flow into the base of Q1 (the value Vbe/R4 is constant), making it conduct more. It also works in the opposite direction.
 17th October 2010, 12:49 PM #7 diyAudio Member     Join Date: Jul 2005 Location: D-55629 Schwarzerden interesting topic. I recall to a special circuit in the German magazine "Funkschau" (diy power amp project approx. 1965) concerning bias stabilization for 2N3055 Circlotron. In the next time I will check old stuff and if I find this article, I will report about that circuit; check out also this: SuSy Circlotron - jFET input Buffer + OPA1632 + 2SK135 http://www.amplimos.it/images/SUMO.pdf SUMO Line CSPP/Cirlotron - Brand Names of Commercial Solid State Amplifiers Are there commercial amp products with the topology according the so called Norton circuit about follow URL? http://www.diyaudio.com/forums/attac...-unigabuff.gif Last edited by tiefbassuebertr; 17th October 2010 at 12:55 PM.
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Location: D-55629 Schwarzerden
from the good known push-pull buffer technology with NPN/PNP BjT's the typical value for the idle current must be between 15mA and 50mA for each power device - mostly 25-30mA.
Can I realize the same idle current values (and the same crossover distortion values at the same time) by this both circlotron topologies?

To bring D1 and D2 in thermal contact with the heatsink of output power devices it would be from the mechanical point a good way to create this diodes from a TO126 BjT like BD139. Are there electrical disadvantage in this case?

In the attachement Elvee's circuit with theory of operation from his post's here so as DC conditions
Attached Files
 Circlomos.Elvee.ckt.pdf (13.6 KB, 357 views)

Last edited by tiefbassuebertr; 18th October 2010 at 06:30 PM.

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Join Date: Sep 2006
Quote:
 Originally Posted by tiefbassuebertr from the good known push-pull buffer technology with NPN/PNP BjT's the typical value for the idle current must be between 15mA and 50mA for each power device - mostly 25-30mA. Can I realize the same idle current values (and the same crossover distortion values at the same time) by this both circlotron topologies?
I think so.
The classic circlotron (all NPN, including the phase splitter) works essentially in a common emitter configuration, very much like older topologies using transformers.
But for those topologies, the optimum quiecent current is in the same range as the more modern, complementary ones

Quote:
 To bring D1 and D2 in thermal contact with the heatsink of output power devices it would be from the mechanical point a good way to create this diodes from a TO126 BjT like BD139. Are there electrical disadvantage in this case?
Note that only one of the diodes has to be in thermal contact with the output devices: coupling both of them would lead to overcompensation.
And the other one is needed to compensate for CCS itself, Q3.
A TO126 seems nice for this function. And if it is a large area transistor, the current density will be small, causing a small overcompensation, which is probably desirable to overcome imperfect thermal coupling.

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Join Date: Jul 2005
Location: D-55629 Schwarzerden
Quote:
 Originally Posted by tiefbassuebertr interesting topic. I recall to a special circuit in the German magazine "Funkschau" (diy power amp project approx. 1965) concerning bias stabilization for 2N3055 Circlotron. In the next time I will check old stuff and if I find this article, I will report about that circuit;
go to post # 45 about
Best topology for no-feedback ClassAB buffer ?

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