I must have changed the symbol names by mistake, because the model did not work for me as is... let me check it out and get back to you.Proposed 6P9P model is good for me. Quick check tells:
230V/-6V/44mA, and
145V/-1,8V/20mA.
Jazbo, typo is in "info part" of first line. Should be ..... P K G2 G.
But this typo does not affect the directive.
Proposed 6P9P model is good for me...
Could you share that 6P9P model ?
Could you please upload the complete .ASC and .SYM files for the 6P9 test circuit, I had to re-install LTSpice and lost all my old files......second data should be:
105V / -1,8V / 20mA
my typo, sorry.
Yes, thanks again. This seems to be the triode model of the pentode only, but the pentode side seems to be very similar to 6GV8 and this model I already have.
You can also try the ECL85P model from the Ayumi library, it should be pretty close to the 6F5P.
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Thanks, I finally got the model to work but I am getting the same results as artosalo... Did you use the same curve data as shown in the picture below?This is a circuit where I quickly tested model from post 592.
Symbol model is tetrode model from Misc folder and LT spice.
1. Ua = 102 V, Ug1 = 0 : Ia = 40 mA
2. Ua = 171 V, Ug1 = -3 : Ia = 38 mA
3. Ua = 242 V, Ug1 = -6 : Ia = 38 mA
So my results show too low anode currents.
6P9 Triode-Connected vs. the datasheet:
An externally hosted image should be here but it was not working when we last tested it.
The model i downloaded is not workin with my tetrode.asy looks like some pins are switched around
Attachments
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Ayumi models always assign the pin numbers from the top to the botton of the tube, e.g., GU50PP A S G K. So just make sure whichever symbol that you use, assigns the pins in the same order. But this particular model was originally intended for TINA, so I don't think it would work in LTSpice at all... try this one instead:
Code:
*
* Generic pentode model: GU50_AN
* Copyright 2003--2008 by Ayumi Nakabayashi, All rights reserved.
* Version 3.10, Generated on Sat Jan 11 08:13:44 2014
* Plate
* | Screen Grid
* | | Control Grid
* | | | Cathode
* | | | |
.SUBCKT GU50_AN A G2 G1 K
BGG GG 0 V=V(G1,K)+0.45288699
BM1 M1 0 V=(0.10715305*(URAMP(V(G2,K))+1e-10))^-1.1401545
BM2 M2 0 V=(0.56814856*(URAMP(V(GG)+URAMP(V(G2,K))/4.0302301)))^2.6401545
BP P 0 V=0.0015719333*(URAMP(V(GG)+URAMP(V(G2,K))/7.0936201))^1.5
BIK IK 0 V=U(V(GG))*V(P)+(1-U(V(GG)))*0.0011497682*V(M1)*V(M2)
BIG IG 0 V=0.00078596663*URAMP(V(G1,K))^1.5*(URAMP(V(G1,K))/(URAMP(V(A,K))+URAMP(V(G1,K)))*1.2+0.4)
BIK2 IK2 0 V=V(IK,IG)*(1-0.4*(EXP(-URAMP(V(A,K))/URAMP(V(G2,K))*15)-EXP(-15)))
BIG2T IG2T 0 V=V(IK2)*(0.916000233*(1-URAMP(V(A,K))/(URAMP(V(A,K))+10))^1.5+0.083999767)
BIK3 IK3 0 V=V(IK2)*(URAMP(V(A,K))+2101.25)/(URAMP(V(G2,K))+2101.25)
BIK4 IK4 0 V=V(IK3)-URAMP(V(IK3)-(0.0011298169*(URAMP(V(A,K))+URAMP(URAMP(V(G2,K))-URAMP(V(A,K))))^1.5))
BIP IP 0 V=URAMP(V(IK4,IG2T)-URAMP(V(IK4,IG2T)-(0.0011298169*URAMP(V(A,K))^1.5)))
BIAK A K I=V(IP)+1e-10*V(A,K)
BIG2 G2 K I=URAMP(V(IK4,IP))
BIGK G1 K I=V(IG)
* CAPS
CGA G1 A 0.1p
CGK G1 K 8.4p
C12 G1 G2 5.6p
CAK A K 9.2p
.ENDS
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Hi everyone,
I'm trying to do a simulation of Bassman 5F6-A (1959) in PSpice. How can I simulate the output transformer? Use magnetic.lib from spice or create a new model? I don't know nothing about the core...
You can modify the values to suit the 5F6-A's OPT:
Code:
.SUBCKT PP_OUTPUT_XFRMR 1 2 3 4 5
* PUSH PULL OUTPUT XFRMR
* 5000 OHM PRIMARY
* 8 OHM SECONDARY
* 100H TOTAL PRIMARY INDUCANCE
*
LP1 1 21 50 ;Henries
RP1 21 2 70 ;ohms
RP2 2 23 70 ;ohms
LP2 23 3 50 ;Henries
LS1 4 5 0.16 ;Henries
CP1 1 3 2NF ; CAPACITANCE
KALL LP1 LP2 LS1 .9999875
.ENDS
Do you know which datasheet the GU-50 model was based on? I am not able to match it to any of the GU/LS/RY-50 datasheets I have seen...Found one thats works
For example, here is one vs. the Telefunken LS50:
An externally hosted image should be here but it was not working when we last tested it.
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GU-50:
I am using next model:
.SUBCKT GU50 1 2 3 4 ; P G1 C G2 (Pentode) 21-Nov-2001
+ PARAMS: MU=8.5 EX=1.350 KG1=800 KP=15.9 KC=8000
+ KVB=30.3 VCT=0.00 RGI=1k
+ CCG=14P CPG1=0.4P CCP=9.2P
RE1 7 0 1G
RE2 8 3 1G
E1 7 0 VALUE= ; E1 BREAKS UP LONG EQUATION FOR G1.
+{V(4,3)/KP*LOG(1+EXP((1/MU+V(2,3)/V(4,3))*KP))}
G1 1 3 VALUE={(PWR(V(7),EX)+PWRS(V(7),EX))/KG1*ATAN(V(1,3)/KVB)}
G2 8 3 VALUE={(PWR(V(7),EX)+PWRS(V(7),EX))/KC*(2.5708-ATAN(V(1,3)/KVB))}
E2 8 4 VALUE={0}
RCP 1 3 1G ;
C1 2 3 {CCG} ;
C2 1 2 {CPG1} ;
C3 1 3 {CCP} ;
R1 2 5 {RGI} ;
D3 5 3 DX ;
.MODEL DX D(IS=1N RS=1 CJO=10PF TT=1N)
.ENDS
and Tetrode-RY symbol
I am using next model:
.SUBCKT GU50 1 2 3 4 ; P G1 C G2 (Pentode) 21-Nov-2001
+ PARAMS: MU=8.5 EX=1.350 KG1=800 KP=15.9 KC=8000
+ KVB=30.3 VCT=0.00 RGI=1k
+ CCG=14P CPG1=0.4P CCP=9.2P
RE1 7 0 1G
RE2 8 3 1G
E1 7 0 VALUE= ; E1 BREAKS UP LONG EQUATION FOR G1.
+{V(4,3)/KP*LOG(1+EXP((1/MU+V(2,3)/V(4,3))*KP))}
G1 1 3 VALUE={(PWR(V(7),EX)+PWRS(V(7),EX))/KG1*ATAN(V(1,3)/KVB)}
G2 8 3 VALUE={(PWR(V(7),EX)+PWRS(V(7),EX))/KC*(2.5708-ATAN(V(1,3)/KVB))}
E2 8 4 VALUE={0}
RCP 1 3 1G ;
C1 2 3 {CCG} ;
C2 1 2 {CPG1} ;
C3 1 3 {CCP} ;
R1 2 5 {RGI} ;
D3 5 3 DX ;
.MODEL DX D(IS=1N RS=1 CJO=10PF TT=1N)
.ENDS
and Tetrode-RY symbol
Hmm, it works but still does not match up to any datasheet that I can find, if you don't mind, could you please post the LS50 curves that you are using for the comparison?Good model Matej. I think that is based on the LS50 curves.
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