Hello I need help
I'm making an inverter welder
Transformer data:
E 71/33/32 N87
For 50v output
I have 13 primary turns 0.67mm x 20 wires and 8 secondary turns 0.67mm x 58 wires.
The problem is:
The secondary coil I want to wind with copper foil not with copper wires
So how can I calculate how many turns of copper foil I have to make? And dimensions of copper foil? Please help
I'm making an inverter welder
Transformer data:
E 71/33/32 N87
For 50v output
I have 13 primary turns 0.67mm x 20 wires and 8 secondary turns 0.67mm x 58 wires.
The problem is:
The secondary coil I want to wind with copper foil not with copper wires
So how can I calculate how many turns of copper foil I have to make? And dimensions of copper foil? Please help
Last edited by a moderator:
Exactly the same number of turns as for wire.
Wire CSA is the same regardless of if it is foil or wire.
for secondry i have 0.67mm x 58 wires
what size of foil i use please help i'm not understanding
and thanks for quickly reply in other forums they reply after 1 month
help
for secondry i have 8 turns of 0,67mm x 58 wires
what size of foil have to use please help im not understanding
Exactly the same number of turns as for wire.
Wire CSA is the same regardless of if it is foil or wire.
for secondry i have 8 turns of 0,67mm x 58 wires
what size of foil have to use please help im not understanding
Please do not use all caps when posting. Read the forum rules, they are here.
I have fixed your post.
sorry
Why do u want to use foil? That is only used in planars where sw-freq is very high, b/c that requires low inductance and few turns. It will likely become very capacitive with that many turns.
i want to make this
Welding inverter 100A
for secondry i have 0.67mm x 58 wires
what size of foil i use please help i'm not understanding
and thanks for quickly reply in other forums they reply after 1 month
Your secondary wire is 0.67mm in diameter ?
so cross section area (csa) of one strand is pi*d*d/4 = 0.35 mm2, right ?
0.35 mm2 times 58 strands = approx. 20 mm2
so you need at least 20 square mm cross section area of your foil.
Thermal properties of foil may be different, I don't know.
Also, if inverter frequency is high, multiple strands of wire is much better because of skin effect.
Last edited:
Your secondary wire is 0.67mm in diameter ?
so cross section area (csa) of one strand is pi*d*d/4 = 0.35 mm2, right ?
0.35 mm2 times 58 strands = approx. 20 mm2
so you need at least 20 square mm cross section area of your foil.
Thermal properties of foil may be different, I don't know.
Also, if inverter frequency is high, multiple strands of wire is much better because of skin effect.
you are a genius man thank you very very much
but one other thing i calculated all with this software diysmps
but one thing is not clear if i have to wind for first primary or secondry turns
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