Netlist said:It will work but as usual in Aleph amplifiers, more is better.
I used six of them in a CRCRC combination. R's are 0.1ohm.
/Hugo
What is the difference when i add the resistor between it?
From practice; you get a big reduction in ripple after every R and a small voltage drop. The smaller the resistor value, the smaller the voltage drop and the smaller the heat dissipation. When choosing bigger value resistors you start wasting too much power and need bigger resistors and heatsinks to cool them.
Not sure if a bigger value, say 0.5ohm has any effect on further decreasing ripple.
Theory is for other people.
/Hugo
Not sure if a bigger value, say 0.5ohm has any effect on further decreasing ripple.
Theory is for other people.
/Hugo
When R = 0.1 and C is 47,000uf,
Xc = 6.28 x 100 (50Hz) x 0.047 = 0.034
R+Xc = (0.1^2+0.034^2)^0.5 = 0.106
Ripple voltage attenuation = 20*log(0.034/0.106) = -10dB
So, better supply voltage regulation . . .
CRC = -10dB
CRCRC = -20dB
My calculation might be incorrect . . . anyhow, I am just trying to demonstrate how the ripple voltage could be reduced by the R . . .
Regards
jh
Xc = 6.28 x 100 (50Hz) x 0.047 = 0.034
R+Xc = (0.1^2+0.034^2)^0.5 = 0.106
Ripple voltage attenuation = 20*log(0.034/0.106) = -10dB
So, better supply voltage regulation . . .
CRC = -10dB
CRCRC = -20dB
My calculation might be incorrect . . . anyhow, I am just trying to demonstrate how the ripple voltage could be reduced by the R . . .
Regards
jh
wuffwaff said:Hi,
I´m using a CLC with 50000uF - 2.2mH - 100000uF per rail. This has even less ripple and doesn´t produce as much heat as resistors.
I´ve used intertechnik torobars and tested them up to 10A without getting into saturation.
William
so less ripple current is better?
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