Official M2 schematic

So,

Second channel done.

3mV offset between R3/R4 legs and DC offset at outputs trimmable to -8mV. So will leave R3/R4 as is but change R7 on this side too to 49k9 to be able to use trimpot range better.

And. Music! :D

Steef
 

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I know IR = Vishay
But does IRFP9240 = SIHFP9240 ? That is, are they manufactured from the same plant to the exact same procedure and materials using the same manufacturing equipment.


To step back a minute.....

It's been established that IR = Vishay = Siliconix

But how does Infineon fit in? It looks like Infineon bought IR, and that Vishay bought IR.... but it looks like Vishay bought only the Infrared part of infineon.

Does Infineon = IR = Vishay = Siliconix = ? Are all four of these the same?
 
Two quick questions:

  1. I have 3mV DC on the EDCOR of both channels. Is it
    • a nice idea
    • don't bother, or
    • a stupid idea (how can you ask)
    to replace R3/R4 combo with one (1) 20R 500mW Bourne trimpot?
  2. On the bench this amp gets HOT. Should I go for a 4U chassis (Modushop 400mm deep dissipate) or is 3U sufficient?
Thanks
Steef
 
I am not sure you are thinking about this in the manner that I intended. Here is an example using the 3U 200mm sink:

A single 3U 200mm sink has 20 fins and measures ~7.75" wide, ~4.75" tall, and has fins that are 1.25" deep.

Total dissipation area for all fins combined = 20 fins * 1.25" deep * 2 sides per fin * 4.75 fin height = 237 sq in
Total dissipation area of one side (the outer side) of the heat sink base plate (the inner side is trapped inside the chassis) = 4.75 * 7.75 = 37 sq in
Total radiating area per 3U sink = 237 + 37 = 275 sq in.

With 275 sq in per sink, you want to limit power dissipation to somewhere between 25 and 30 watts per sink for a 25c temp rise.

This exactly matches my F4 that dissipates 100w for two channels and uses four 3U sinks (total of ~1000 sq inches). 1000 sq inches / 100w dissipation = 10 sq in/watt :D
 
Actually a bit less
(24V*2)*1.3A=<65W

Thanks for the clarification - I had recorded ~75-80wpc dissipation in my notes. Thank you for catching my error. I have a pair of sinks that I previously thought were too small, but now I'm thinking they are a better match :D

Still want somewhere near 10sq in of sink per dissipated watt. I'd bet a 9:1 ratio would work as well, it would just be hotter...
 
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Joined 2003
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I am not sure you are thinking about this in the manner that I intended. Here is an example using the 3U 200mm sink:

A single 3U 200mm sink has 20 fins and measures ~7.75" wide, ~4.75" tall, and has fins that are 1.25" deep.

Total dissipation area for all fins combined = 20 fins * 1.25" deep * 2 sides per fin * 4.75 fin height = 237 sq in
Total dissipation area of one side (the outer side) of the heat sink base plate (the inner side is trapped inside the chassis) = 4.75 * 7.75 = 37 sq in
Total radiating area per 3U sink = 237 + 37 = 275 sq in.

With 275 sq in per sink, you want to limit power dissipation to somewhere between 25 and 30 watts per sink for a 25c temp rise.

This exactly matches my F4 that dissipates 100w for two channels and uses four 3U sinks (total of ~1000 sq inches). 1000 sq inches / 100w dissipation = 10 sq in/watt :D

I have the 300 version, more than adequate. Gets warm, nothing like Aleph J. If you want dual mono, go with 400
 
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Joined 2003
Paid Member
Ah, this makes more sense to me! The 4U x 300mm deep = 565sq in per sink. Divide 565 by 65w = 8.6 sq in per dissipated watt. This works. But put an Aleph-J in this same chassis (565 sq in/ 100w) = 5.6 sq in per watt - things will be much hotter!

Actually, my Aleph j is in the same case. It is a little hotter, but still not bad at all. I can keep my hands on the sinks as long as I want...but it is hotter. The M2 isn't really much hotter than the F6 was when it was in that case.

Russellc