BTL is for mono right? If I want to run BTL, I should solder a 22k resistor there, rite?
I have extra boards and 4 pieces of TDA2050 with me.
This sch does not differentiate between Signal Return and Speaker Return+Power Ground.
It omits the RF attenuator at the input and omits the damped Output Inductor.
The ratio C1:C2 is wrong.
It is C2 that desperately needs to be much bigger in relation to C1.
I totally agree.
Feedback pole = 15.9 Hz
Input pole = 4.9 Hz
Perfect combination for distortion. It is the input pole that must always be the dominant pole, preferably by a factor of 10. This way the feedback capacitor has virtually no effect on the performance of the circuit.
C2= 100 uF moves the feedback pole down to 1.59 Hz. In practice this works fine with an input pole of 4.9 Hz, since both poles are low enough to be effectively unobtrusive.
With C2 so large, you want to add anti-latch up (clamp) diodes to C2.
I see so many circuits that ignore this basic principle. To me it's a no brainer.
I have been giving this advice for years, but few if any bother to read it.
I picked it up from a Member many years ago and tried it in a couple of amplifiers and it proved to me that it was the right way to do it.
Having used the advice and having gained that knowledge, when I read D.Self and others on the distortion effects of capacitors (when used as filters), it all falls into place.
There are some who disagree.
I picked it up from a Member many years ago and tried it in a couple of amplifiers and it proved to me that it was the right way to do it.
Having used the advice and having gained that knowledge, when I read D.Self and others on the distortion effects of capacitors (when used as filters), it all falls into place.
There are some who disagree.
Exactly. And it's especially true for the typical capacitor we would use in this application.
With empirical science?
This makes a measurable and sometimes audible difference. Is the sky green? (Syd Barret aside
)In summary, the amount of distortion a capacitor can introduce into a circuit is directly proportional to the ratio of the capacitor's impedance to the impedance of the network it's in.
Apply this principle with C2 = 10 uF, f = 20 Hz.
Now apply this principle with C2 = 100 uF, f = 20 Hz.
Any questions?
Apply this principle with C2 = 10 uF, f = 20 Hz.
Now apply this principle with C2 = 100 uF, f = 20 Hz.
Any questions?
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